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QveST [7]
3 years ago
10

There are 4 blue, 6 green, 4 yellow, and 10 black marbles in a a bag . If one marble is picked at random, what is the probabilit

y of not picking a green marble.
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0
The probability is 18/24


good luck
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Plz help me solve this. and any song requests
LuckyWell [14K]

Answer:

66

Step-by-step explanation:

12(8)-9(8-6)-(12-9)(8)÷2=96-18-12      or   6(9)+(12-9)(8)/2=54+12

                                     = 66                                              =66

3 0
3 years ago
Read 2 more answers
F(x)= 9-x^2, x ≥ 0. f^-1(x)=??
julia-pushkina [17]
y=9-x^{2},\ x\ge0

Reverse x and y:
x=9-y^{2},\ y\ge0
Solve for y:
x=9-y^{2}
\rightarrow y^{2}=9-x
\rightarrow y=\sqrt{9-x} since y\ge0
7 0
3 years ago
What cell generates energy for all the other cells (it’s for science but it doesn’t show science as a subject so yes)
Harlamova29_29 [7]

lol, that would be biology

but I'd say its the mitochondria

5 0
3 years ago
90 3/7 was a demical
LenKa [72]
90.42857143 or
90.4 to nearest decimal
6 0
3 years ago
Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,
Dmitry_Shevchenko [17]

Answer:

\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250

Step-by-step explanation:

Given:

T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}

now we need to solve this integral!

T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}

T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0

T = \left|-1250e^{-0.04t}\right|^{\infty}_0

T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})

when any number has a power of negative infinity it is 0. because: a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0, like something being divided by a very large number!

T = (-1250(0))-(-1250e^0)

T = 1250

this is the total amount of waste

6 0
3 years ago
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