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QveST [7]
3 years ago
10

There are 4 blue, 6 green, 4 yellow, and 10 black marbles in a a bag . If one marble is picked at random, what is the probabilit

y of not picking a green marble.
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0
The probability is 18/24


good luck
You might be interested in
The 50th term of an arithmetic sequence is 86 and the common difference is 2.  Find the first three terms of the sequence.
Nesterboy [21]
a_n=a_{n-1}+d=a_{n-2}+2d=\cdots=a_1+(n-1)d

which means

a_{50}=86=a_1+49\times2\implies a_1=-12

which in turn means the next two terms are a_2=-10 and a_3=-8.
6 0
3 years ago
perter's glasses each hold 8 fluid ounces.how many glasses of juice can perter pour from a bottle that holds 5 quarts
NeX [460]

Answer:

8 glasses :)

Step-by-step explanation:

There is 32oz per quart. 8 goes in to 32 a total of four times. So since there are two quarts, Peter can pour 8 glasses.

From everything I've seen it should be 2 quarts from my knowledge. Sorry if this doesn't help!

3 0
3 years ago
What’s the answer to this?
inna [77]

Since the triangle is equilateral, all its angles are equal to 60°

AO is the bisector⇒∠OAD = 30°

AO is the hypotenuse, ∠OAD = 30°⇒

OD=5*2=10m

By the Pythagorean theorem

10^2=AD^2+5^2\\AD=\sqrt{100-25} \\AD=\sqrt{75}

AC=AD+DC=2\sqrt{75}=10\sqrt{3}

S=\frac{a^2\sqrt{3} }{4}

S=\frac{(10\sqrt{3})^2\sqrt{3}  }{4} =\frac{300\sqrt{3} }{4} =75\sqrt{3} m^2

Answer: A) S=75\sqrt{3}m²

P.S. Hello from Russia and sorry for my bad english :^)

3 0
2 years ago
If the basketball player scored 15 baskets out of 21 tries. How many tries would it take to score 20 baskets?
Evgen [1.6K]
28 tries. The ratio is 5:7, so once you multiply 5 by 4 to get 20, you do the same to 7 to get 28.
6 0
2 years ago
A newly hired basketball coach promised a high-paced attack that will put more points on the board than the team’s previously te
puteri [66]

Answer:

a. z = 2.00

Step-by-step explanation:

Hello!

The study variable is "Points per game of a high school team"

The hypothesis is that the average score per game is greater than before, so the parameter to test is the population mean (μ)

The hypothesis is:

H₀: μ ≤ 99

H₁: μ > 99

α: 0.01

There is no information about the variable distribution, I'll apply the Central Limit Theorem and approximate the sample mean (X[bar]) to normal since whether you use a Z or t-test, you need your variable to be at least approximately normal. Considering the sample size (n=36) I'd rather use a Z-test than a t-test.

The statistic value under the null hypothesis is:

Z= X[bar] - μ  = 101 - 99 = 2

σ/√n 6/√36

I don't have σ, but since this is an approximation I can use the value of S instead.

I hope it helps!

7 0
3 years ago
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