Question

Please help and explain, thanks so much. 2x^3 y^8 / 4y^2

Answer 1

Answer:

$2 {x}^{3} {y}^{8} \div 4 {y}^{2} \\ = {x}^{3} {y}^{8} \div 2 {y}^{2} \\ = {x}^{3} {y}^{8 - 2} \div 2 \\ = {x}^{3} {y}^{6 } \div 2 \: \: \: ans$

Step-by-step explanation:

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