In the triangles below, mzB = m2P and mZT = MZJ.
1 answer:
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Answer:
y = tan(60°)x = (√3)x
Step-by-step explanation:
The usual translation between polar and rectangular coordinates is ...
... y = r·sin(θ)
... x = r·cos(θ)
If we solve the second equation for r, we get
... x/cos(θ) = r
Now, we can substitute this into the first equation with the result ...
... y = (x/cos(θ))·sin(θ) = x·tan(θ)
Our polar equation is θ = 60°, so we can substitute this value into the relation we have for x and y:
... y = x·tan(60°)
... y = (√3)x
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The portion of the line in the 3rd quadrant corresponds to r values that are negative. The given polar equation has no restriction against that.
