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Answer:
The sum of 3 consecutive integers is 13 more than twice the smallest integer. Find the integer.
x + (x+1) + (x+2) = 2x + 13
3x + 3 = 2x + 13:
3x - 2x = 13 - 3
x = 10 is the smallest integer:
Check: 10 + 11 + 12 = 2(10) + 13