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asambeis [7]
3 years ago
5

In the input/output rule: y = -2x + 8 What

Mathematics
1 answer:
Doss [256]3 years ago
3 0

Answer:

"input" is x and "output" is y

y= -2(3) +8

y= -6 +8

y= 2

your answer would be 2

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Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0
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--------------------------------------------------------------------------------

Use PEMDAS:

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E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

h(x)=\dfrac{1}{3}|x-6|+4

Put the values of x to the equation of the function h(x):

x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6


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