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3 years ago

Which number has a 3 that 10 times greater than the 3 in 513?

Mathematics

1 answer:

cestrela7 [59]3 years ago

3 0

The 3 in "513" is only 3. it's 1, 2, 3. If we do 3 x 10 it's 30

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A company uses paper cups shaped like cones for its water cooler. Each cup has a height of 10cm, and the base has a radius of 4.

prohojiy [21]

Answer: the answer is 150 :)

Step-by-step explanation: Volume of a cone is

V = 1/3 pi * r^2 *h

The volume of one cone is

pi = 3.14

r = d/2 = 6/2 =3

h=9

Substitute what we know

V = 1/3 * (3.14) * (3^2) * (9)

= 27* 3.14

= 84.78 cm^3

The water cooler has 12717 cm^3 water

Divide the water by the volume of the paper cup cone and we will know how many paper cup cones we can fill, assuming we fill them completely.

12717/ 84.78 = 150

We can fill 150 paper cup cones. have a great day!

8 0

2 years ago

Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$

The sum of the first ten terms is -85

-----------------------

As a check for $S_{10}$ , here are the first ten terms:

t1 = 5
t2 = 2
t3 = -1
t4 = -4
t5 = -7
t6 = -10
t7 = -13
t8 = -16
t9 = -19
t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that $S_{10} = -85$ is correct.

6 0

2 years ago

I need help write expression in exponential from

podryga [215]

3. 5x5x5. i am not sure if i am correct but i am assuming it is that.

5 0

3 years ago

Does anybody know the correct answer?

d1i1m1o1n [39]

Answer:

arithmetic

Step-by-step explanation:

hope it helped

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3 years ago

Work out the area of triangle ABC<br> 2 root 5 cm <br> 3 root 2 cm

shusha [124]

Shouldn’t there be a picture?

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2 years ago