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stepan [7]
3 years ago
10

. Write a word problem for this equation: $14 - x = $3 ​

Mathematics
1 answer:
jenyasd209 [6]3 years ago
6 0

Answer:

I have 14 dollars. I went to the store to buy a book, and now I only have 3 dollars

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Pls helppppp and explain how to answer
34kurt
Well, the place is charging him 115/hr
and he's booked it for 6hrs

how much is going to be his cost? well \bf \cfrac{115}{hr}\cdot 6hr\implies 690

now, there will be 14 teams playing, so... if we divide 690 evenly among the 14 teams, that means each team will need to pay 690/14 about 49.28571 or 49 bucks and 29 cents about

now, if each team pays that much, they'll cover 690, so Dylan has his cost covered, however, for a profit, a profit is surplus, so, in order to make surplus income, or profit, he'll need to charge "more than" 49.29
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3 0
3 years ago
Find two positive numbers satisfying the given requirements. The product is 216 and the sum is a minimum. (No Response) (smaller
fgiga [73]

Answer:

x1=\sqrt{216} \  and \ y1=\ \sqrt{216}

Step-by-step explanation:

Let the first number is x1 and other number is y1 then

x1 * y1 =216

Therefore

y1=\frac{216}{x1}

also there sum is

s1 =x1+y1....Eq(1)

Putting the value of y1  in the previous equation

s1\ =x1 + \frac{216}{x1}........Eq(2)

Differentiate the the Eq(2) with respect to x1 we get

\frac{ds1}{dx1} \ =\ 1+216*\frac{1}{-x1^{2} }

\frac{ds1}{dx1} \ =\ 1-\frac{216}{x1^{2} }\ =\ 0

{x1^{2} }\ =\ 216\\  x1=\sqrt{216}

Putting the value of X1 in Eq(1) we get

y1=\frac{216}{\sqrt{216} } \\y1=\frac{216*\sqrt{216} }{216} \\y1=\ \sqrt{216}

So x1=\sqrt{216} \  and \ y1=\ \sqrt{216}

6 0
4 years ago
Which of the following uses the reciprocal property to rewrite x/5 = 72/4<br><br> Please help me :)
vova2212 [387]

Answer:

??You texted incomplete question.

By the way, x = 90

3 0
3 years ago
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