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Alja [10]
3 years ago
9

I NEED HELP now pls pls

Mathematics
2 answers:
just olya [345]3 years ago
7 0
Pythagoras theorem ! (a²+b²=c²)

Q1) AC = √4.8²+3.6²
= √36
= 6cm

Q2) AB= √17.55² - 6.75²
= √262.44
= 16.2cm

Q3) BC= √14² - 6²
= √160
= 12.64911
= 12.6 cm (to 3sf)
Len [333]3 years ago
4 0

Answer:

1) AC = 6 cm

2) AB = 16.2 cm      ( note that ^{2} is = square and \sqrt{  this is = square root)

3) BC = 12.65cm

Step-by-step explanation:

1) a^{2} + b^{2} = c^{2}

4.8^{2} + 3.6^{2} = AC^{2}

36 = AC^{2}

\sqrt{ }36 = AC

AC = 6

2)   a^{2} + b^{2} = c^{2}

AB^{2} + 6.75^{2} = 17.55^{2}

AB^{2} = 308.0025 - 25.5625

AB = \sqrt{ }262.44

AB = 16.2

3)  a^{2} + b^{2} = c^{2}

BC^{2} + 6^{2} = 14^{2}

BC^{2} = 196 - 36

BC = \sqrt{ } 160

BC = 12.65

I hope this helps a little bit.

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Step-by-step explanation:

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The two non-parallel sides of an isosceles trapezoid are each 7 feet long. The longer of the two bases measures 22 feet long. Th
Orlov [11]

The length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

<h3>How to determine the length</h3>

The cosine rule is given as;

c = \sqrt{a^2 + b^2 - 2ab cos \alpha }

c = length of the diagonal

a = base length = 22 feet

b = 7 feet

c = \sqrt{7^2 + 22^2 - 2 * 7 * 22 cos 40}

c = \sqrt{533 - 308 * 0. 7660}

c = \sqrt{533 - 235. 93}

c = \sqrt{297. 072}

c = 17. 24 feet

Using sine rule

\frac{a}{sin A }  = \frac{c}{sin C}

\frac{a}{sin 70}  = \frac{17. 24}{sin 40}

Cross multiply

a × sin 60 = c × sin 70

a × 0. 8660 = 17. 24 × 0. 9397

a = \frac{16. 20}{0. 8660}

a = 18. 7 feet long

Thus, the length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

Learn more about  isosceles trapezoid here:

brainly.com/question/10187910

#SPJ1

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2 years ago
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