It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
it doesn't exist
Step-by-step explanation:
the expression 0×7/11 is equivalent to 0. 1/0 isn't possible, so its reciprocal doesn't exist.
Answer:
Step-by-step explanation:
m∠JXM + m∠NXP = 180° - m∠MXN = 90°
L has "x -3"
S has "x"
x + x - 3 = 17
2x -3 (+3) = 17 (+3)
2x = 20
2x/2 = 20/2
x = 10
Leona has x - 3, or 10 - 3, or 7 dollars
Skye has 10 dollars
hope this helps
