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PSYCHO15rus [73]

3 years ago

9

Mr. Thompson's sixth grade class is competing in the school field day. There are 16 boys and 12 girls in his class. He divided t

he class into the greatest

1 answer:

murzikaleks [220]3 years ago

8 0

Answer:

You have to finish the question.

Step-by-step explanation:

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Every month, Mr. Leroy pays his rent through automatic payments (withdrawals) from his

GarryVolchara [31]

Answer:

-445/month

Step-by-step explanation:

I think that what you would do is divide -5,341 by 12, which gives you -445

6 0

3 years ago

Write an equation of the line whose slope is -2 and whose y-intercept is 1.

musickatia [10]

Y=-2x+1 ~~~~~~~~~~~~~~~~~

4 0

3 years ago

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Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285

Mkey [24]

Answer:

$Highway = 155\ miles$

$City = 130\ miles$

Step-by-step explanation:

Given

$Highway = 31mi/gallon$

$City = 26mi/gallon$

$Total\ Miles = 285$

$Total\ Gallons = 10$

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

$c + h = 10$ ---- gallons used

and

$31h + 26c = 285$ --- distance travelled

In the first equation, make c the subject

$c = 10 - h$

Substitute 10 - h for c in the second equation

$31h + 26c = 285$

$31h + 26(10 - h) = 285$

Open bracket

$31h + 260 - 26h = 285$

Collect like terms

$31h - 26h = 285 - 260$

$5h = 25$

Make h the subject

$h = \frac{25}{5}$

$h = 5$

Substitute 5 for h in $c = 10 - h$

$c = 10 - 5$

$c = 5$

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

$Highway = 31 * 5$

$Highway = 155\ miles$

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

$City = 26 * 5$

$City = 130\ miles$

8 0

3 years ago

(3squared)squared x(10cubed)squared

kiruha [24]

Hii :))

$\tt {(3 ^{2} )}^{2} \times {(10^{3}) }^{2} \\ \tt = (3 \times 3) ^{2} \times {(10 \times 10 \times 10)}^{2} \\ \tt \: = {9}^{2} \times 1000 ^{2} \\ \tt = (9 \times 9) \times (1000 \times 1000) \\ = \tt \: 81 \times 1000000 \\ = \boxed{\tt \: 81000000}$

__________________

$\overbrace{ \underbrace{ \mathfrak{ \: \infty \: Carry \: on \: Learning \: \infty }}}$

ᴛʜᴇᴇxᴛʀᴀᴛᴇʀᴇꜱᴛʀɪᴀʟ

3 0

3 years ago

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Do the rays BA and AB define the same ray? In complete sentences, explain why the two rays are the same or why the two rays are

Deffense [45]

Rays are named according to their endpoints, the first one named is the "starting" endpoint, the second one is the one that will continue on into infinity. Therefore, ray BA has a terminal endpoint at B and goes through point A into infinity. Ray AB has a terminal endpoint at A and goes through point B into infinity. Definitely NOT the same ray.

7 0

3 years ago