4 years ago

How many solutions does the system have

Mathematics

1 answer:

astraxan [27]4 years ago

6 0

Answer:

x=-3, y=-5 & x=1, y=3. The system have two solutions.

Step-by-step explanation:

x^2+4x-2=2x+1

x^2+4x-2x-2-1=0

x^2+2x-3=0

factor out the trinomial

(x+3)(x-1)=0

zero property

x+3=0, x-1=0

x=0-3=-3

x=0+1=1

y=2(-3)+1=-6+1=-5

y=2(1)+1=2+1=3

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