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Vilka [71]
3 years ago
9

Help please i appreciate it

Mathematics
2 answers:
Dimas [21]3 years ago
4 0
I’m pretty sure it would be c
Alekssandra [29.7K]3 years ago
4 0
It’s C!! Hope this helps!
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Step-by-step explanation:

Θ is in quad IV

sin = -√2 / 2

cos = √2 / 2

tan = -1

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A ratio that compares two quantities measured in different units is a conversion factor!
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Y = 1/2x +10 y = 4x - 4 solve by graphing
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You are choosing between two health clubs. Club A offers membership for a fee of $ 28$28 plus a monthly fee of $ 20.$20. Club B
eimsori [14]

Answer:

That is to say that at 3 months, the values of the club are equal.

Club A = 268 dollars in total

Club B = 295 dollars in total

Step-by-step explanation:

The first thing is to propose an equation for each club. Let m be the number of months.

Club A = 28 + 20 * m

Club B = 19 + 23 * m

Now, to know when it is the same, we must equal the value of Club A with Club B, it would look like this

28 + 20 * m = 19 + 23 * m

By rearranging the equation we have:

23 * m - 20 * m = 28-19

3 * m = 9

m = 3

That is to say that at 3 months, the values of the club are equal.

Now to know the total value, we will do it with an annual membership, which would be a total of 12 months, therefore it is to replace in the equation of each one:

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3 0
3 years ago
You are creating an open top box with a piece of cardboard that is 16 x 30“. What size of square should be cut out of each corne
Arada [10]

Answer:

\frac{10}{3} \ inches of square should be cut out of each corner to create a box with the largest volume.

Step-by-step explanation:

Given: Dimension of cardboard= 16 x 30“.

As per the dimension given, we know Lenght is 30 inches and width is 16 inches. Also the cardboard has 4 corners which should be cut out.

Lets assume the cut out size of each corner be "x".

∴ Size of cardboard after 4 corner will be cut out is:

Length (l)= 30-2x

Width (w)= 16-2x

Height (h)= x

Now, finding the volume of box after 4 corner been cut out.

Formula; Volume (v)= l\times w\times h

Volume(v)= (30-2x)\times (16-2x)\times x

Using distributive property of multiplication

⇒ Volume(v)= 4x^{3} -92x^{2} +480x

Next using differentiative method to find box largest volume, we will have \frac{dv}{dx}= 0

\frac{d (4x^{3} -92x^{2} +480x)}{dx} = \frac{dv}{dx}

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⇒\frac{dv}{dx} = 12x^{2} -184x+480

taking out 12 as common in the equation and subtituting the value.

⇒ 0= 12(x^{2} -\frac{46x}{3} +40)

solving quadratic equation inside the parenthesis.

⇒12(x^{2} -12x-\frac{10x}{x} +40)=0

Dividing 12 on both side

⇒[x(x-12)-\frac{10}{3} (x-12)]= 0

We can again take common as (x-12).

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We have two value for x, which is 12 and \frac{10}{3}

12 is invalid as, w= (16-2x)= 16-2\times 12

∴ 24 inches can not be cut out of 16 inches width.

Hence, the cut out size from cardboard is \frac{10}{3}\ inches

Now, subtituting the value of x to find volume of the box.

Volume(v)= (30-2x)\times (16-2x)\times x

⇒ Volume(v)= (30-2\times \frac{10}{3} )\times (16-2\times \frac{10}{3})\times \frac{10}{3}

⇒ Volume(v)= (30-\frac{20}{3} ) (16-\frac{20}{3}) (\frac{10}{3} )

∴  Volume(v)= 725.93 inches³

6 0
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