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3 years ago

Help please help please

Mathematics

2 answers:

ANTONII [103]3 years ago

7 0

Answer is C. 22

if you subtract 15 by 10, you get 5. so you can also subtract 27 by 5 and get 22

anzhelika [568]3 years ago

3 0

∆ABC is similar to ∆DEF (SAS),

AB/DE = AC/DF
27/x = 15/10
15x = 270
x = 18

The length of DE is 18 units.

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2 years ago

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3 years ago

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2 years ago

The variables x and y vary directly. Use the given values to write an equation that relates x and y: x = 4, y = -16

Gnesinka [82]

Vary Directly: y = k*x

Vary Inversely: y = k/x

Because x and y vary directly, our equation will look like the first one.

y = k*x

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4 0

3 years ago

. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).

devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = $\frac{360}{n}$

Therefore, angle at the center of a dodecagon = $\frac{360}{12}$ = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = $\frac{1}{2}.(a).(b).sin\theta$

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = $\frac{1}{2}.(3).(3).sin30$

= $\frac{9}{4}$

Area of dodecagon = 12×area of the small triangle

= 12× $\frac{9}{4}$

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

4 0

2 years ago