Alkaline earth metals
Group 13 aka the boron family is categorized as alkaline earth metals
Answer:
One offspring would have red leaves.
Explanation:
Given
Yellow leaves are dominant and red leaves are recessive
Let us assume that the trait of Yellow color of a leaf be represented by "Y"
and the trait of red color of a leaf be represented by "y"
When two parent of genotype "Yy" are crossed with each other, the following offsprings are produced as shown in the punnet square below
Y y
Y YY Yy
y Yy yy
Total four offpsrings are produced out of which only one has red leave as red color is a recessive trait and it will appear only when both the allele in a cell are of red color.
Thus, one offspring would have red leaves.
Hydrogen is similar to electricity. Although an electric vehicle, for an example, doesn't create any tail pipe emissions from the vehicle, that may not be the case where the electricity was made. If the electricity was made from an old, smoking, worn out gasoline powered generator in order to charge the electric vehicle, the total pollution created would be much more than that made by a regular gasoline car. However, if the electricity is made by an environmentally friendly renewable source, such as solar or wind, then the total pollution created in powering the electric vehicle would be much less, perhaps even zero.
<span>Hydrogen can be made from electricity or petroleum. If made from petroleum it wouldn't be much different than gasoline because the rest of the petroleum would have to be used somewhere. If the hydrogen is made from electricity then the question again is where is the electricity being made. </span>
<span>Your question is also a good one because it highlights the "high use" of renewable energy. The production and use of hydrogen in less efficient than running just off of electricity. So you'd have to produce a whole lot more electricity to make hydrogen to drive a car a certain distance than to charge a battery-electric car and drive the same distanc</span>
Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. In addition, suppose that a dominant allele (L) codes for long eyelashes and a recessive allele (l) codes for short eyelashes. If two individuals heterozygous for both traits (tail color and eyelash length) mate, the probability of the phenotypic combinations of the offspring will be in the ratio, D. 9:3:3:1 ratio (9 polka-dot tails and long eyelashes, 3 polka-dot tails and short eyelashes, 3 solid tails and long eyelashes, 1 solid tail and short eyelash).
The solution is found by solving a Punnett square shown in the image.
