3 years ago

Someone Please help me on this question!

Mathematics

1 answer:

Scilla [17]3 years ago

4 0

Answer:

A. $g(x) = \sqrt[3]{x} + 3$

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makvit [3.9K]

I'm assuming you meant to write 8^(-2) or $8^{-2}$ where the -2 is the exponent over the 8.

If my assumption is correct, then we use the rule $a^{-b} = \frac{1}{a^b}$

So,

$a^{-b} = \frac{1}{a^b}\\\\8^{-2} = \frac{1}{8^2}\\\\8^{-2} = \frac{1}{64}$

<h3>Answer: Choice D. 1/64</h3>

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The answer to this is - + 3

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