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lozanna [386]
3 years ago
8

Find x- and y-intercepts. Write ordered pairs representing the points where the line crosses the axes. Note x-intercept is a poi

nt on the x-axis. So the y-coordinate of this point is equal to 0. the y-intercept is a point on the y-axis. So x-coordinate of this point is equal to 0. 2x+3y=6
Mathematics
2 answers:
GenaCL600 [577]3 years ago
5 0
Your answer would be -2/3 and that is in slope y-intercept is (0,2)
lutik1710 [3]3 years ago
4 0
Slope: -2/3
y-intercept: (0,2)
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Perimeter = 16x + 8<br> The length of the indicated side is
Dahasolnce [82]

Answer:

d

Step-by-step explanation:

Because you need to substitute the variable first, multiply that and add 8.

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3 years ago
Select the most appropriate unit to measure the horizontal distance between the two ends of this loop.
ruslelena [56]

Hello!


The appropriate unit to measure the horizontal distance between the two ends of the loop is B, feet. Why?


Choice A, miles, seems not proportionate because rollercoaster loops wouldn't be a mile long.

Choice C, centimeters, is 0.01 of a meter, and that's way too small.

Finally choice D, inches, imagine a quarter, that's how long an inch is.


So therefore, your choice is correct, which is choice B.

5 0
3 years ago
Read 2 more answers
B=1/4Af <br> im supposed to solve for A
meriva
2 coz (x)-1=0
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2=|3x|
8 0
3 years ago
Plz show work 3x-5=1/2x+2x
Troyanec [42]
3x - 5 = 1/2x + 2x 3x - 5 = .5x + 2x3x - 5 = 2.5x-3x     = -3x   -5= -.5x   divide by -.5 on both sidesx = 10
8 0
3 years ago
In recent years, only 79% of the fruit sold at Fred's Fruit stand has been any good. Fred recently started buying fruit from new
Juli2301 [7.4K]

Answer:

The p-value of the test is 0.0485 < 0.05, also less than 0.07, so there is sufficient evidence to conclude that there is a statistically significant increase in the percentage of good fruit, for both significance levels, thus the change in significance levels do not change the conclusion.

Step-by-step explanation:

79% of the fruit sold at Fred's Fruit stand has been any good. Test if there has been an increase.

At the null hypothesis, we test if there has been no increase, that is, the proportion is still of 79%, so:

H_0: p = 0.79

At the alternative hypothesis, we test if there has been an increase, that is, more than 79% being good, so:

H_1: p > 0.79

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.79 is tested at the null hypothesis:

This means that \mu = 0.79, \sigma = \sqrt{0.79*0.21}

In a random sample if 475 pieces, 85 were bad.

So 475 - 85 = 390 were good, and:

n = 475, X = \frac{390}{475} = 0.8211

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.8211 - 0.79}{\frac{\sqrt{0.79*0.21}}{\sqrt{475}}}

z = 1.66

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.8211, which is 1 subtracted by the p-value of Z = 1.66.

Looking at the z-table, z = 1.66 has a p-value of 0.9515.

1 - 0.9515 = 0.0485

The p-value of the test is 0.0485 < 0.05, also less than 0.07, so there is sufficient evidence to conclude that there is a statistically significant increase in the percentage of good fruit, for both significance levels, thus the change in significance levels do not change the conclusion.

5 0
3 years ago
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