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Firlakuza [10]
3 years ago
12

Please help with this question ​

Mathematics
1 answer:
motikmotik3 years ago
3 0

Answer:

Step-by-step explanation:

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Give one example of when would use the friendly numbers strategy to substract. Explain why
Andrei [34K]
Here is one example of when you would use the friendly number strategy to subtract.
42 - 18

We will turn the 18 into a friendly number, which is going to be 20. 

(42 + 2) - (18 + 3)
44 - 20
Now it is easier to subtract 44 - 20 than it is 42 -18. With 42 - 18 we would have to barrow whereas with 44 -20 we do not have to barrow and we can do it in our head easier and makes it faster.
6 0
3 years ago
The distance from a star to a planet is approximately 90,000,000 miles. If light travels at a rate of 186,000 miles per​ second,
algol13
So to get this the easiest way would be to:
-put 90,000,000 over 186,000 and cancel out zeroes so you have 90,000 divided by 186 ( so it makes more sense in long division later)
-Then divide 90,000 by 186
-get 483.87 seconds
Hope this helped!

7 0
3 years ago
Read 2 more answers
Your parents are building a pool that is 7 ft wide and 12 ft long. They want to put a walkway around the pool that is x ft wide
Luden [163]

Answer:

25 /12*6 =12.5

Step-by-step explanation:

thats what i got

5 0
3 years ago
1
Nadusha1986 [10]

Answer: 181.46 square inches

Step-by-step explanation:

Area = pi ˣ r squared

Since the radius (half of diameter) is 7.6 inches, then it should equal to 181.46 square inches.

6 0
4 years ago
A rectangular garden has a length of (2y - 4) feet and a width of 4y^2 feet. How do you find the perimeter of the garden
Ber [7]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{8 {y}^{2}  + 4y - 8}}}}}

Step-by-step explanation:

Given,

Length of a rectangular garden ( l ) = 2y - 4

Width of a rectangular garden ( w ) = 4y²

Perimeter of the garden = ?

<u>Finding</u><u> </u><u>the</u><u> </u><u>perimeter</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u><u> </u><u>having </u><u>length </u><u>of</u><u> </u><u>2</u><u>y</u><u>-</u><u>4</u><u> </u><u>and</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>4</u><u>y</u><u>²</u>

\bold{ \boxed{ \sf{perimeter \: of \: a \: rectangle = 2(l + w)}}}

\longrightarrow{ \sf2(2y - 4 + 4 {y}^{2}})

Distribute 2 through the parentheses

\longrightarrow{ \sf{4y - 8 + 8 {y}^{2} }}

Arrange it in standard form

\longrightarrow{ \sf{8 {y}^{2}  + 4y - 8}}

Hope I helped!

Best regards! :D

3 0
4 years ago
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