Question

Find the equation of the line with a slope of 4 and passing through (0,3)

Answer 1

The equation of the line with a slope of 4 and passing through (0,3) is

4 x - y + 3 = 0

Explanation:

Slope, m = 4

Points = ( 0,3 ) -  ($x_{1}$, $y_{1}$)

Equation of the line = ?

We know,

The formula used to find the equation of a line when points and slope are given is

                                            (y - $y_{1}$) = m ( x - $x_{1}$)

Where, $x_{1}$ and $y_{1}$are the points

            m is the slope

Therefore,

y - 3 = 4 ( x - 0)

y - 3 = 4 x

4 x - y + 3 = 0

Therefore, The equation of the line with a slope of 4 and passing through (0,3) is 4 x - y + 3 = 0

           

Answer 2

4x -  y + 3 =0 is the equation of the line

Step-by-step explanation:

Given:

The slope of the line  =  5

The points through with the line passes = (0,3)

To Find:

The equation of the line  =?

Solution:

The equation  y = mx + b

where m is the slope and (0,b) is the y-intercept.

The slope is given which is m = 4 and a point (0,3)

Then you can use slope-point equation

$y - y_o = m(x - x_o)$

where $(x_o,y_o)$ is the given point

y - (3) = 4(x - 0)

y - 3 = 4(x)

y = 4x - 22

y - 3 = 4x

4x - y + 3 = 0