<span>First and third results are coherent. They both represent a probability of 0.9. Because 9 out of 10 is 9/10 = 0.9, and 135 out of 150 = 135 / 150 = 0.9. Nevertheless, second result is not coherent because 32 out of 50 is 32/50 = 0.64. I think this number must be discarded, and use 0.9 as the experimental probaility. That means that for 300 trials you should obtain x / 300 = 0.9 => x = 0.9 * 300 = 270. Then, the answer is that you can expect that a yellow ball will be selected 270 times out of 300. </span>
Answer:
1
Step-by-step explanation:
Given :
Mean, μ = 4
Standard deviation, s = 0.8
Sample size, n = 30
The distribution is independent.
Z = (x - μ) / s /sqrt(n)
Probability that downtime period is between 1 and 5
P(1≤ x ≤ 5) :
[(x - μ) / (s /sqrt(n))] ≤ Z ≤ [(x - μ) / (s /sqrt(n))]
[(1 - 4) / (0.8 /sqrt(30))] ≤ Z ≤ [(5 - 4) / (0.8 /sqrt(30)]
[-3 / 0.1460593] ≤ Z ≤] 1 / 0.1460593]
P(-20.539602 ≤ Z ≤ 6.8465342)
P(Z ≤ 6.8465342) - P(Z ≤ - 20.5396)
P(Z ≤ 6.8465342) = 1 (Z probability calculator)
P(Z ≤ - 20.5396) = 0 (Z probability calculator)
1 - 0 = 1
Answer:
D
Step-by-step explanation:
Using the Altitude- on- hypotenuse theorem
DF² = CD × DE , substitute values
12² = 6 DE
144 = 6 DE ( divide both sides by 6 )
24 = DE → D
Answer: 0
Explanation is on the picture
