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zloy xaker [14]
3 years ago
10

a. Plot the data for the functions ƒ(x) and g(x) on a grid. x -2 -1 0 1 2 ƒ(x) 1 4 16 x -1 0 1 2 3 g(x) 3 4 5 6 7 b. Identify ea

ch function as linear, quadratic, or exponential, and use complete sentences to explain your choices. c. Describe what happens to the function values in each function as x increases from left to right. d. At what value(s) of x are the function values equal? If you cannot give exact values for x, give estimates.

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

Part A:

The plot for the function f(x) and g(x) is attached. The purple curve represents f(x) and the black line represents g(x).

Part B:

The graph of f(x) shows that f(x) is an exponential function.

The graph of g(x) shows that g(x) is a linear function.

Part C:

As x increases from left to right, the function f(x) increases very rapidly.

As x increases from left to right, the function f(x) increases at a constant rate.

Part D:

From the graph it can be seen than the valus of x for which the values of the function are equal are: x = -4 and x = 1.19.

Step-by-step explanation:

I hope this helps

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Answer:

5c^2 +6c +13

Step-by-step explanation:

so we can see than 5c^2

and 13c - 7c are the same = 6c

and 4 +9 = 13

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Step-by-step explanation:

There isn't a picture or a description Dude

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4 years ago
The polynomial p(x)=3x^3-20x^2+37x-20 has a known factor of (x-4). Rewrite p(x) as a product of linear factors. p(x) =
vesna_86 [32]

Answer:

p(x) = (3x^{2} - 8x + 5)(x - 4)

Step-by-step explanation:

p(x) has degree 3

(x - 4) has degree 1

So p(x) can be rewritten as a polynomial of degree 2 multiplying (x-4)

So

p(x) = (ax^{2} + bx + c)(x - 4)

To find a, b and c, we have to divide p(x) by x - 4.

So

Finding a:

Dividing the first term of p(x) by x - 4.

\frac{3x^{3}}{x - 4} = 3x^{2}

So a = 3.

Now multiplying 3x² by, x - 4, we have:

3x^{2}(x - 4) = 3x^{3} - 12x^{2}

Subtracting p(x) from this:

3x^{3} - 20x^{2} + 37x - 20 - (3x^{3} - 12x^{2}) = 3x^{3} - 20x^{2} + 37x - 20 - 3x^{3} + 12x^{2} = -8x^{2} + 37x - 20

Finding b:

Dividing the first term, after the subtraction, by x - 4.

\frac{-8x^{2}}{x - 4} = -8x

So b = -8.

Multiplying -8x by x - 4, we have:

-8x(x-4) = -8x^{2} + 32x

Then

-8x^{2} + 37x - 20 - (-8x^{2} + 32x) = -8x^{2} + 37x - 20 + 8x^{2} - 32x = 5x - 20

Finding c:

\frac{5x}{x - 4} = 5

So c = 5.

Just to verify if the remainder is 0.

5(x - 4) = 5x - 20

5x - 20 - (5x - 20) = 0

Ok

Then:

p(x) = (ax^{2} + bx + c)(x - 4)

p(x) = (3x^{2} - 8x + 5)(x - 4)

7 0
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Step-by-step explanation:

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I hope this helps!

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Step-by-step explanation:

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