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2 years ago

Round the number to the given degree of accuracy. 3.478 nearest unit

Mathematics

1 answer:

Anon25 [30]2 years ago

3 0

9514 1404 393

Answer:

Step-by-step explanation:

The digit to the right of the units digit is the tenths digit. It is 4. Because it is not 5 or greater, that digit and all to its right are simply dropped. The rounded value of 3.478 is 3.

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HHHHHHEEEELLLLLLPPPPP

sveticcg [70]

We want to check how many intersections line A and B have, that is, we want to check how many common solutions do these equations have:

i) 2x + 2y = 8

ii) x + y = 4

use equation ii) to write y in terms of x as : y=4-x,

substitute y =4-x in equation i):

2x + 2y = 8
2x + 2(4-x) = 8
2x+8-2x=8
8=8

this is always true, which means the equations have infinitely many common solutions.

Answer: There are infinitely many solutions.

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2 years ago

Which relationship is a function?

Sladkaya [172]

Answer:

The 4th one

Step-by-step explanation:

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3 years ago

What is the slope of (-3,-2) and (-1,-5)

klio [65]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0

ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .

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3 years ago

Jordan writes 3(4x – 8) = 12x – 8

Ivahew [28]

Hi! What’s -8 times 3?

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2 years ago