First lets find -8.2 x 10 = -82 know we find 82^5 which is 82*82*82*82*82
-82*-82=6724 and then 6724*-82= -551368 and then -551368*-82 =45212176 and then 45212176*-82= -3707398432 and finally -3707398432 is our answer i checked the calc to after i did the hard math that took me forever i had some help from the calc and i got this hopefully this helps
Answer:
$618,253.61
Step-by-step explanation:
30 to 65 is 35 years
22000 × (1 + 10/100)³⁵
22000 × 1.1³⁵
618253.6107
The final answer for this question is 591.28 cubic cm
Answer:
Step-by-step explanation:
x^3 - 8x² - x + 8 =0
x^3 - 8x² - (x - 8 )=0
x²(x-8) - (x-8) = 0
(x-8)(x² -1) =0
x-8 = 0 or x² - 1 = 0
x-8=0 or (x-1)(x+1)=0
x=8 x=1 or x=-1
Power and chain rule (where the power rule kicks in because
):

Simplify the leading term as

Quotient rule:

Chain rule:


Put everything together and simplify:






