Question

f(5)=12 for a geometric sequence that is defined recursively by the formula f(n)=0.3*f(n-1), where n is an integer and n>0. Find f(7). Round your answer to the nearest hundredth.

Answer 1

Subsitute 7 for n
f(7)=0.3*f(7-1)
f(7-1)=f(6)
find f(6)
f(6)=0.3*f(6-1)
f(6-1)=f(5)=12

sub
f(7)=0.3*(0.3*12)
f(7)=1.08

Answer 2

Answer:

f(7) = 1.08

Step-by-step explanation:

Given that:

f(5) = 12

A geometric sequence that is defined recursively by the formula

$f(n) = 0.3 \cdot f(n-1)$       .....[1 ] where, n is an integer and n> 0.

Substitute n = 6 in [1] we have;

$f(6) = 0.3 \cdot f(5)$

Using f(5) = 12 we have;

$f(6) = 0.3 \cdot 12$

⇒$f(6) =3.6$

We have to find f(7).

Substitute n = 7 in [1] we have;

$f(7) = 0.3 \cdot f(6)$

Substitute the given values f(6) = 3.6 we have;

$f(7) = 0.3 \cdot 3.6$

Simplify:

f(7) = 1.08

Therefore, the value of f(7)to the nearest hundredth is, 1.08