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slega [8]
2 years ago
15

Please help please please

Mathematics
2 answers:
Svetradugi [14.3K]2 years ago
5 0

Answer:

The Answer Is 70

Step-by-step explanation:

So first you have do the parentheses, (2+5) = 7

Then do the exponents 7^{2} 7.7 = 49

Next do the Multiplying 49.5= 214

Finally Subtract 284-214=70

<em>I Hope This Helps You :)</em>

Luda [366]2 years ago
4 0

Answer:

39

Step-by-step explanation:

284-5(7)²

284-(5×49)

284-245

39

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Step-by-step explanation:

8 0
2 years ago
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Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?
Flura [38]

Answer:

The value to the given expression is 8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3

To find the value of the given expression:

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}

( By using the property ((\frac{a}{b})^m=\frac{a^m}{b^m} )

=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}

( By using the property (ab)^m=a^mb^m )

=\frac{(10^{12})(5^6)}{(10^9)(5^9)}

( By using the property (a^m)^n=a^{mn} )

=(10^{12})(5^6)(10^{-9})(5^{-9})

( By using the property \frac{1}{a^m}=a^{-m} )

=(10^{12-9})(5^{6-9}) (By using the property a^m.b^n=a^{m+n} )

=(10^3)(5^{-3})

=\frac{10^3}{5^3} ( By using the property a^{-m}=\frac{1}{a^m} )

=\frac{1000}{125}

=8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Therefore the value to the given expression is 8

3 0
3 years ago
Read 2 more answers
NEEED HELPPP !!!!!!!!!!
serious [3.7K]

Answer:

X + 7 + 2x + 19 = 35

Add like terms

3x + 26 = 35

-26          -26

3x = 9

/3   /3

X = 3

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mojhsa [17]

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f(2) = 2(2)^{2} + 5 \sqrt{(2)+2}

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3 0
3 years ago
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Wewaii [24]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
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