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3 years ago

Match the solution set given in inequality with the best solution set given in interval notation

Mathematics

1 answer:

zimovet [89]3 years ago

7 0

There you go

I hope this help you

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Carson is training for a race. He ran 12.56 miles on one day and 12.98 miles the next day. How much farther did he run the secon

taurus [48]

Answer:

.42 miles more

Step-by-step explanation:

12.98 minus 12.56

6 0

3 years ago

This is really easy i just dont get it

boyakko [2]

Answer:

x=1

Step-by-step explanation:

We wanna have the same amount on both sides

There are 3 circles on the left and 7 circles on the right. There are also 4 triangles. Turn into numbers...

4x+3=7

4x=7-3

x=1

We can check by substituting one

7=7

7 0

3 years ago

Country A, Country B, and Country C won a total of 130 medals. Country B won 10 more medals than Country C. Country A won 38 m

snow_lady [41]

Answer:

Country A = 84

Country B = 28

Country C = 18

Step-by-step explanation:

Country A, Country B, and Country C won a total of 130 medals;

A + B + C = 130 ......1

Country B won 10 more medals than Country C;

B = C + 10 .......2

Country A won 38 more medals than the total amount won by the other two;

A = B + C + 38 ........3

Substituting equation 3 to 1;

(B+C+38) + B+C = 130

2B + 2C + 38 = 130 .......4

Substituting equation 2 into 4;

2(C+10) + 2C + 38 = 130

4C + 58 = 130

4C = 130-58 = 72

C = 72/4 = 18

B = C + 10 = 18 + 10 = 28

A = B + C + 38 = 18 + 28 + 38 = 84

Country A = 84

Country B = 28

Country C = 18

8 0

3 years ago

Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.

Mkey [24]

Answer:

$1.~e^{-2} \\2.~e^{\frac{7}{2}}\\3.~e^8\\4.~e^{\frac{-11}{2}}$

Step-by-step explanation:

We have to simplify the given exponential exponents.

Exponential Properties:

$e^0 =1\\e^a.e^b = e^{a+b}\\\\\displaystyle\frac{e^a}{e^b} = e^{a-b}\\\\(e^a)^b = e^{ab}\\\\e^{-a} = \frac{1}{e^a}$

Simplification takes place in the following manner:

$(e^{-3})^\frac{2}{3}\\(e^a)^b = e^{ab}\\=e^{-3\times \frac{2}{3}}\\=e^{-2}$

$(e^4)(e^{\frac{-1}{2}})\\e^a.e^b = e^{a+b}\\=e^{(4+\frac{-1}{2})} \\= e^{\frac{7}{2}}$

$(e^{-2})^{-4}\\(e^a)^b = e^{ab}\\= e^{-2\times -4}\\=e^8$

$(e^{-4})(e^{\frac{-3}{2}})\\e^a.e^b = e^{a+b}\\=e^{(-4+\frac{-3}{2})} \\= e^{\frac{-11}{2}}$

4 0

3 years ago

Which coordinate pair is a solution of the linear

Alika [10]

Answer:

The answer is (-8,10).

6 0

3 years ago

Read 2 more answers