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3 years ago

What is the sum of 1/12 plus 3/8 in a fraction? A.1/6 B.1/5 C.11/48 D.11/24

Mathematics

2 answers:

Nataliya [291]3 years ago

7 0

The correct answer is 11/24

Nuetrik [128]3 years ago

6 0

D.11/24
1/12=2/24
3/8=9/24
2/24+9/24=11/24

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Algebraically determine if the relation y = x3 − 4x is symmetric with respect to the x-axis, y-axis, the origin or has no symmet

Gala2k [10]

$\bf y=x^3-4x
\\\\\\
\textit{check for y-axis symmetry}\\\\
\stackrel{x=-x}{y=(-x)^3-4(-x)}\implies y=(-x)(-x)(-x)+4x\implies \boxed{y=-x^3+4x}
\\\\\\
\textit{checking for x-axis symmetry}\\\\
\stackrel{y=-y}{(-y)=x^3-4x}\implies -y=x^3-4x\implies \boxed{y=-x^3+4x}
\\\\\\
\textit{checking for origin symmetry}\\\\
\stackrel{x=-x\qquad y=-y}{(-y)=(-x)^3-4(-x)}\implies -y=(-x)(-x)(-x)+4x
\\\\\\
-y=-x^3+4x\implies y=\cfrac{-x^3+4x}{-1}\implies \boxed{y=x^3-4x}\quad \checkmark$

notice, if you replace x = -x and y = -y accordingly for each test for symmetry, if the resulting function, is equal to the original function, then it has that type of symmetry.

7 0

3 years ago

Please Help!!!<br> Due: Monday<br> On Ellipses - Pre Calc

eduard

25. <u>Step-by-step explanation:</u>

$\text{The general form of an ellipse is:}\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1\\\\\bullet \text{(h, k) is the Center}\\\bullet \text{a is the radius of x}\\\bullet \text{b is the radius of y}\\\bullet \text{the largest value between a and b is the major}\\\bullet \text{the smallest value between a and b is the minor}\\\bullet \text{the vertices are the (h, k) value plus the major (a or b) value}\\\bullet \text{the co-vertices are the (h, k) value plus the minor (a or b) value}\\\bullet \text{Length is the diameter}=2r\\$

$\dfrac{x^2}{16}+\dfrac{y^2}{25}=1\quad \text{can be rewritten as}\ \dfrac{(x-0)^2}{4^2}+\dfrac{(y-0)^2}{5^2}=1\\\\\bullet (h, k)=(0,0)\\\bullet a=4\\\bullet b=5\\\bullet \text{b is the largest value so: b is the major and a is the minor}\\\bullet \text{Vertices are }(0, 0+5)\ and\ (0, 0-5)\implies (0, 5)\ and\ (0, -5)\\\bullet \text{Co-vertices are }(0+4, 0)\ and\ (0-4, 0)\implies (4,0)\ and\ (-4,0)\\\bullet \text{Length of major is }2b:2(5)=10\\\bullet \text{Length of minor is }2a:2(4)=8$

To find the foci, first we must find the length of the foci using the formula:

$(r_{major})^2-(r_{minor})^2=c^2$

Then add the c-value to the h (or k)-value that represents the major.

b² - a² = c²

25 - 16 = c²

9 = c²

±3 = c

The center is (0, 0) and the major is the y-value so the foci is:

(0, 0+3) and (0, 0-3) ⇒ (0, 3) and (0, -3)

26. Answers

Follow the same steps as #25:

Center: (0, 0)

Vertices (7, 0) and (-7, 0)

Co-vertices: (0, 3) and (0, -3)

foci: (2√10, 0) and (-2√10, 0)

length of major: 14

length of minor: 6

5 0

3 years ago

The area of the rectangular floor in Tamara’s room is 9556 square feet. The width of the room is 813 feet. Part A Round each mea

denis23 [38]

Answer:

Area of Tamara room

=9556 square feet

Width

=813 feet

Length= 11.75 feet

Total area= 19794 square feet

480 square feet will not be enough

Step-by-step explanation:

Dimensions of Tamara's room to the nearest whole numbers

Area of Tamara room

=9556 square feet

Width

=813 feet

For the length

Length*width= area

Length= area/width

Length= 9556/813

Length= 11.75

To the nearest whole number = 12 feet

The ceiling is 12 feet high

Let's calculate for the area of the combination

1)Height and width two times

2)Height and length two times

1).area = 12*813

= 9756

Then 9756*2= 19512

2). area= 12*11.75

= 141

Then 141*2= 282

Total area = 282+19512

Total area= 19794

7 0

3 years ago

A set of three numbers with the greatest common factor of 13

BigorU [14]

78, 130, and 91. You're welcome :D

3 0

3 years ago

Find the value of cos 0 , If sec 0 = 3/2 0 < 90

UNO [17]

Answer:

Step-by-step explanation:

cos theta is 2/3 because cos means reciprocal of sec

7 0

3 years ago

Read 2 more answers