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3 years ago

THIS IS THE LAST QUESTION ON MY PACKET WHOEVER ANSWERS GETS BRAINLIEST AND 50 POINTS

Mathematics

2 answers:

atroni [7]3 years ago

8 0

Answer:

It’s B

Step-by-step explanation:

max2010maxim [7]3 years ago

3 0

Answer:

Step-by-step explanation:

3 8/9 - 1/3

1/3=3/9

3 8/9 - 3/9= 3 5/9

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Please help me , fast

Vesnalui [34]

Answer:

0.3 with the hat ? the answer is first no, then it's a repeated decimal.

Step-by-step explanation:

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3 years ago

To become a member of the book-of-the-month club there is a $40 sign-up fee and a $2 monthly fee. What is the total cost of bein

bija089 [108]

$40 sign up + ($2 monthly fee x 19)
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2 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

3 years ago

Plzzzz help mee plzzzzz plzzzzz

FromTheMoon [43]

Answer:

1. B

2. Seven Hundred thousand nine hundred and four

Step-by-step explanation:

3 0

3 years ago

Triangle G F E is cut by line segment H J. Line segment H J goes from side G E to F E. The length of G F is 4 x minus 4, the len

alexira [117]

Answer:

HJ = 8 JE = 4

Step-by-step explanation:

it is given that H is the midpoint of GE and J is the midpoint of FE. According to the midpoint theorem the line segment connecting the midpoint of two sides is parallel to the three side and its length is half of the third side. since JH is connecting the midpoints.

HJ= 1/2 (GF)

x + 3 = 1/2 (4x - 4)

x + 3 = 2x - 2

x = 5

^ Thus meaning the value of x is 5.

Now you just fill into your equations:

HJ = x + 3 = (5) + 3 = 8

JE = x - 1 = (5) - 1 = 4

Therefore, HJ = 8; JE = 4.

5 0

3 years ago