Answer:
g(x) = -5x²
(option B)
Step-by-step explanation:
we know that our original graph, f(x) = x² is a parabola.
So, we can consider what happens when we adjust the function/equation of a parabola.
when we "vertically stretch" a parabola, we are increasing the value of x.
think of it this way: the steepness of a slope is rise over run. If we rise ten, and run one, that's going be a lot more steep than if we rise 1, run 1.
Let's say our x = 5
if f(x)=x²
f(5) = 25
> y value / steepness is 25
f(x) = 3x²
f(5) = 75
> y value / steepness is 75
So, we are looking for an equation with an increase in x present.
When a parabola has been flipped over the x-axis, we know that the original equation now includes a negative
suppose that x = 1
if y = x² ; y = 1² = 1
if y = -(x²) ; y = -(1²) ; y = -1
So, when we set x to be negative, we make our y-values end up as negative also (which makes the graph look as if it has been flipped upside-down)
This means that we are looking for a function with a negative x value.
So, we are looking for a negative x-value that is multiplied by a number >1
The graph that fits our requirements is g(x) = -5x²
hope this helps!!
