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Aleksandr [31]
3 years ago
8

Sec (63°- θ)- cosec (27° + θ)​

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
Sec(63- theta) - cosec( 27+ theta)
sec(63-theta) -sec[90-(27+theta)]
sec(63-theta) -sec(63- theta)
= 0
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Answer: 0.2

Step-by-step explanation:

The first hundred natural numbers are 1 to 100.

Now, the numbers that are multiples of 5 are the numbers that end in 5 or 0, so we have:

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So in the range, we have 20 multiples of 5.

Now, when we select at random, each number has the same probability of being selected, then the probability of randomly selecting a multiple of 5 is equal to the number of multiples of 5 divided the total number of options in the set.

we have 20 multiples of 5, and in the set we have a total of 100 numbers, then the probability is:

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