All categories

3 years ago

PPPPPPPPPPPPPLLLLLLLLLLLLLLZZZZZZZZZZZZZZZ HELP!!!!!!!!! A. B. C. D.

Mathematics

1 answer:

shepuryov [24]3 years ago

3 0

I think the answer is A.

You might be interested in

Pls help meeeee<br> This is about to be due

telo118 [61]

Answer:

3:123 4:0 5:13.69

Step-by-step explanation:

I hope this helps

4 0

2 years ago

Suppose that y varies inversely with x.Write an equation for the inverse variation Y=4 when x=7

myrzilka [38]

Answer:

If y varies inversely as x, then we write it as:

y = k/x

where k is some constant.

If we multiply both sides of this equation by x we get an equation for k:

k = x*y

We are given that y=4 when x=7, therefore:

k = 7*4 = 28

Put this back into our original equation to get:

y = 28/x

4 0

3 years ago

What is linear expansivity?

katrin [286]

Its a type of thermal expansion and described by fractions that represents the fractional increase length of a thin beam of a material exposed to its temperature increase of one degree celcious,"

4 0

3 years ago

The population of a city is modeled by the equation P(t)=232012e0.23t where t is measure in years. If the city continues to grow

Gennadij [26K]

In around 6.35 years, the population will be 1 million.

<h3> how many years will it take for the population to reach one million?</h3>

The population is modeled by the exponential equation:

$P(t) = 232,012*e^{0.23*t}$

Then we just need to solve the equation for t:

$P(t) = 232,012*e^{0.23*t} = 1,000,000$

Let's solve that:

$232,012*e^{0.23*t} = 1,000,000\\\\e^{0.23*t} = 1,000,000/232,012 = 4.31\\$

If we apply the natural logarithm to both sides:

$ln(e^{0.23*t}) = ln(4.31)\\\\0.23*t = ln(4.31)\\\\t = ln(4.31)/0.23 = 6.35$

So in around 6.35 years, the population will be 1 million.

If you want to learn more about exponential equations:

brainly.com/question/11832081

#SPJ1

5 0

1 year ago

Can some one help me plz??

Hitman42 [59]

The answer is C for this question

5 0

3 years ago