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3 years ago

6

I need help with #53 to #60 ASAP … please help this I don’t understand this …. I need to get it done before Monday … can someone

please help me with it

1 answer:

hodyreva [135]3 years ago

8 0

Answer:

the condition of having an abnormally (typically dangerously) low body temperature

Step-by-step explanation:

plz mark me as a brainliest

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A desk is on sale for $135.20, which is 26% of the regular price. What is the regular price?

Nady [450]

Answer:

420$

Step-by-step explanation:

8 0

3 years ago

Given the equation Square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution.

Kisachek [45]

Do recall that squaring and the *radical sign* cancel each other out... like so:( $\sqrt{a}$ ) $^{2}$ = a

When you put it that way, it isn't enough :P
( $\sqrt{a}$ ) $^{2}$ = a
( $\sqrt{8x+1}$ ) $^{2}$ =?

so you start with
( $\sqrt{8x+1}$ ) $^{2}$ = $(5)^{2}$
8x+1=25 <-- subtract 1 to both sides
8x=24 <- divide 8 to both sides
x= 3

To find out if it's an extraneous solution ask yourself: It mustn't result in a radical that I like to call... 'illegal'. Plug it into the radicand 8x+1 and make sure you get something that is not a negative number.... so, DO you get a negative number when you plug in x = 3 into the radicand?

(extraneous solution is a invalid solution)

x=3 not extraneous

6 0

3 years ago

Read 2 more answers

The surface area of a rectangular prism is 115 square inches. What are possible dimensions of the prism?

Delvig [45]

I think D? not to sure

7 0

4 years ago

In addition sentence 7 + 4=11 the 7 is the addend the 11 is the sum what is the name of the 4

romanna [79]

It is called a augend.

4 0

3 years ago

4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

4 years ago