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Paraphin [41]
3 years ago
11

where do I go to ask help from a tech and internet expert. security and protection. I'm open to suggestions and guesses​

Computers and Technology
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

from my own experience, the best place to call is your local Best Buy store. they have a group of technicians called the Geek Squad, and you can either call them for tech support or protection suggestions, or have them do maintenance on a device (both in store and at home)

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Try using the inv command to find the inverse of the matrix Notice the strange output. Include your command and the output in yo
denpristay [2]

Answer:

a)

inv([1 1; 100 100])

warning: matrix singular to machine precision

warning: called from ATest at line 1 column1

ans =

Inf Intf

Inf Inf

b)

A = [4, 9; 5, 11]

B = inv(A)

A*B

B*A

4. 9

5 11

-11.0000 9.0000

5.0000 4.0000

ans . 00000 -0.00000

0 . 00000 1.00000

ans 1.00000 0.00000

0.00000 1.00000

c)

x = [5; 10]

y = A*x

x = [5; 10]

y=

110 135"

d)

B * y is

5.0000

10.0000

e)

B * y

ans 5.0000

10.0000

3 0
3 years ago
HELPPPPP 20 POINTS CORRECT ANSWER GETS BRAINLIEST<br>sorry wrong amount of points ;-;
Vinvika [58]

Answer:

C

Explanation:

6 0
3 years ago
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PLZZ HELP
kap26 [50]

Answer:

Explanation:

Keep in mind a lossy algorithm will lose information while a lossless algorithm maintains all your original information.

Therefore:

A. False, a lossy algorithm will not allow perfect reconstruction.

B. True, if you don't care about keeping all your information it's easier to compress.

C. False, you can use a lossless algorithm for anything.

D. False, the point of lossless is that you keep all information.

4 0
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If I wanted to repeat an action such as a heading for a paper, it would be helpful to _____. create a citation create a caption
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Um... Copy and paste
7 0
4 years ago
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Write a program that prompts the user to enter two characters and display the corresponding major and year status. The first cha
nydimaria [60]

Answer:

  1. import java.util.Scanner;  
  2. public class Main {
  3.    public static void main(String[] args) {
  4.        Scanner input = new Scanner(System.in);
  5.        System.out.print("Please enter two characters: ");
  6.        String inputStr = input.nextLine();
  7.        if(inputStr.charAt(0) == 'B' || inputStr.charAt(0) == 'b'){
  8.            System.out.println("Biology");
  9.        }
  10.        else if(inputStr.charAt(0) == 'C' || inputStr.charAt(0)== 'c'){
  11.            System.out.println("Computer Science");
  12.        }
  13.        else if(inputStr.charAt(0) == 'I' || inputStr.charAt(0) == 'i')
  14.        {
  15.            System.out.println("Information Technology and Systems");
  16.        }
  17.        else{
  18.            System.out.println("Invalid major");
  19.        }
  20.        int num = Character.getNumericValue(inputStr.charAt(1));
  21.        if(num >= 1 && num <= 4){
  22.            switch (num){
  23.                case 1:
  24.                    System.out.println("freshman");
  25.                    break;
  26.                case 2:
  27.                    System.out.println("sophomore");
  28.                    break;
  29.                case 3:
  30.                    System.out.println("junior");
  31.                    break;
  32.                case 4:
  33.                    System.out.println("senior");
  34.                    break;
  35.            }
  36.        }
  37.        else{
  38.            System.out.println("Invalid year status");
  39.        }
  40.    }
  41. }

Explanation:

The code consists of two main parts. The part 1 is to validate the input major and print out the major according to the input character (Line 10 -22). If the input character is not matched with the target letters, a message invalid major will be displayed.

The part 2 is to validate the year status to make sure it only fall within the range of 1-4  (Line 26 -45). If within the range, the program will display the year major accordingly. If not a message invalid year status will be displayed.

4 0
4 years ago
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