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slamgirl [31]
3 years ago
5

Suddenly, though, just as the procedure was about to be relayed to the astronauts, the pressure . . . the temperature . . . drop

ped! And . . . stayed down. The frozen slug, apparently, had melted! (Probably due to the extreme heat in the fuel line.) Problem solved.
—Team Moon: How 400,000 People

Landed Apollo 11 on the Moon,

Catherine Thimmesh


Why does the author include the NASA scientists’ attempts to fix the fuel line?


to show that not all problems need to be solved

to show that the scientists’ hard work had not paid off

to show that many solutions can be failures

to show that the situation was tense for everyone


i wiil give you brainliest answer!
Computers and Technology
2 answers:
nydimaria [60]3 years ago
6 0

Answer:The answer is D.

Explanation:I did the assignment on edge

konstantin123 [22]3 years ago
5 0

Answer:

D)to show that the situation was tense for everyone

Explanation:

got it right on edge

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Please help! i need to answer this soon!
natali 33 [55]

Answer:

1. a modem connects a computer to the internet  

4. a modem transmits digital signals over a telephone line

5. a dial-up modem communicates using a telephonic call​

All of three mentioned above.

Modem stands for modulator de-modulator, and it connects the computer to the internet. Its not the fastest, which is router. And the connection is established via the telephone line, through which the digital signals is being transmitted, And the type used is dial up communication.

Explanation:

The answer is self explanatory.

4 0
3 years ago
2. A data catalog identifies all of the following, except: a. Attribute data type b. Attribute range of values c. Attribute cons
alexandr1967 [171]

Answer:

c. Attribute constraints

Explanation:

A data catalog identifies all of the following, except: "Attribute constraints"

The above statement is TRUE because a Data Catalog, a metadata management service, operates by searching for key data, understand and manage data for usefulness.

Data Catalog checks on the BigQuery datasets, tables, and views and checks both technical and business metadata by identifying the following attributes:

1. Data type

2. Range of values

3. Value for Instructor ID

5 0
3 years ago
How does a paper prototype minimize constraints when compared to a digital one
aksik [14]

A regular prototype minimizes constraints if compared to a paper one because possible problems in use can be identified easily.

<h3>What is a prototype?</h3>

This refers to the initial model of a product designed to test the features of the model before it is released to the market.

<h3>What are the differences between digital and paper prototypes?</h3>

Online protoypes are often time-saving, however, because some features of the prototype cannot be tested, a regular protoype is much better to identify possible problems in design or use.

Learn more about prototipes in: brainly.com/question/4622383

#SPJ1

6 0
2 years ago
A perfect binary tree is a complete binary tree with all levels fully filled. Add a method in the BST class to return true if th
algol [13]

Answer:

class BST {

static class Node

{

int val;

Node left, right;

}

static boolean checkPerfectBT(Node node, int h, int d)

{

if (node == null)

return true;

 

if (node.left == null && node.right == null)

{

if(h==d+1)

return true;

else

return false;

}

 

if (node.left == null || node.right== null)

return false;

 

return checkPerfectBT(node.left, h, d+1) && checkPerfectBT(node.right, h, d+1);

}

static int height(Node node)

{

int dep = 0;

while (node != null)

{

node = node.right;

dep=dep+1;

}

return dep;

}

static boolean isPerfectBT(Node node)

{

int h = height(node);

return checkPerfectBT(node, h, 0);

}

 

static Node addNode(int x)

{

Node node = new Node();

node.val= x;

node.right = null;

node.left = null;

return node;

}

public static void main(String args[])

{

int i,j,k;

Node node= null;

node = addNode(34);

node.left = addNode(2);

node.right = addNode(322);

 

node.left.left = addNode(21);

node.left.right = addNode(23);

node.right.left = addNode(37);

node.right.right = addNode(54);

 

if (isPerfectBT(node) == true)

System.out.println("This is a Perfect Binary tree");

else

System.out.println("This is Not a perfect Binary Tree");

}

}

Explanation:

  • Calculate the depth of BST by using a while loop until it reaches a null value.
  • In the addNode method, make an object of Node class.
  • In the main method, pass the values to addNode method.
  • Finally display the relevant message to show if it's Perfect or not.
6 0
3 years ago
Add three methods to the Student class that compare twoStudent objects. One method (__eq__) should test for equality. A second m
shusha [124]

Answer:

class Student(object):

def __init__(self, name, number):

self.name = name

self.scores = []

for count in range(number):

self.scores.append(0)

 

def getName(self):

 

return self.name

 

def setScore(self, i, score):

 

self.scores[i - 1] = score

 

def getScore(self, i):

 

return self.scores[i - 1]

 

def getAverage(self):

 

return sum(self.scores) / len(self._scores)

 

def getHighScore(self):

 

return max(self.scores)

def __eq__(self,student):

return self.name == student.name

 

def __ge__(self,student):

return self.name == student.name or self.name>student.name

 

def __lt__(self,student):

return self.name<student.name

 

def __str__(self):

return "Name: " + self.name + "\nScores: " + \

" ".join(map(str, self.scores))

 

 

def main():

student = Student("Ken", 5)

print(student)

for i in range(1, 6):

student.setScore(i, 100)

print(student)

 

print("\nSecond student")

student2 = Student("Ken", 5)

print(student2)

 

print("\nThird student")

student3 = Student("Amit", 5)

print(student3)

 

print("\nChecking equal student1 and student 2")

print(student.__eq__(student2))

 

print("\nChecking equal student1 and student 3")

print(student.__eq__(student3))

 

print("\nChecking greater than equal student1 and student 3")

print(student.__ge__(student3))

 

print("\nChecking less than student1 and student 3")

print(student.__lt__(student3))

if __name__ == "__main__":

5 0
3 years ago
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