Question

The tree diagram below shows all of the possible outcomes for flipping three coins. A tree diagram has outcomes (H, H, H), (H, H, T), (H, T, H), (H, T, T), (T, H, H), (T, H, T), (T, T, H), (T, T, T). What is the probability that at least two of the coins will be TAILS? StartFraction 1 over 8 EndFraction StartFraction 3 over 8 EndFraction One-half Three-fourths

Answer 1

Answer:

3 over 8

Step-by-step explanation:

Answer 2

Answer:

The probability that at least two of the coins will be TAILS is one-half.

Step-by-step explanation:

The probability of an event, E is the ratio of the number of favorable outcomes to the total number of outcomes.

$P(E) =\frac{n(E)}{N}$

The experiment consisted of tossing three coins together.

The possible outcomes are as follows:

S = {(H, H, H), (H, H, T), (H, T, H), (T, H, H), (H, T, T), (T, H, T), (T, T, H), (T, T, T)}

n (S) = 8

The outcomes where we get at least two Tails are:

s = {(H, T, T), (T, H, T), (T, T, H), (T, T, T)}

n (s) = 4

Compute the probability that at least two of the coins will be TAILS as follows:

$P(\text{At least 2 TAILS})=\frac{n(s)}{n(S)}$

                                 $=\frac{4}{8}\\\\=\frac{1}{2}$

Thus, the probability that at least two of the coins will be TAILS is one-half.