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balandron [24]
3 years ago
12

The tree diagram below shows all of the possible outcomes for flipping three coins. A tree diagram has outcomes (H, H, H), (H, H

, T), (H, T, H), (H, T, T), (T, H, H), (T, H, T), (T, T, H), (T, T, T). What is the probability that at least two of the coins will be TAILS? StartFraction 1 over 8 EndFraction StartFraction 3 over 8 EndFraction One-half Three-fourths
Mathematics
2 answers:
kati45 [8]3 years ago
8 0

Answer:

3 over 8

Step-by-step explanation:

nydimaria [60]3 years ago
6 0

Answer:

The probability that at least two of the coins will be TAILS is one-half.

Step-by-step explanation:

The probability of an event, E is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E) =\frac{n(E)}{N}

The experiment consisted of tossing three coins together.

The possible outcomes are as follows:

S = {(H, H, H), (H, H, T), (H, T, H), (T, H, H), (H, T, T), (T, H, T), (T, T, H), (T, T, T)}

n (S) = 8

The outcomes where we get at least two Tails are:

<em>s</em> = {(H, T, T), (T, H, T), (T, T, H), (T, T, T)}

n (<em>s</em>) = 4

Compute the probability that at least two of the coins will be TAILS as follows:

P(\text{At least 2 TAILS})=\frac{n(s)}{n(S)}

                                 =\frac{4}{8}\\\\=\frac{1}{2}

Thus, the probability that at least two of the coins will be TAILS is one-half.

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