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Zina [86]
3 years ago
12

Both +33 and -33 are how units from zero

Mathematics
2 answers:
Yuliya22 [10]3 years ago
8 0
If you’re asking how many units they are away from zero, they are 33 units away from zero!!
SashulF [63]3 years ago
4 0

Both +33 and -33 are units of zero because both start from 0.

<h3>Explanation:-</h3>

This is because, -33 starts from the left side of zero, whereas, +33 starts after some numbers in zero. Either left or right, as they both have a common number 0, therefore, <u>-</u><u>3</u><u>3</u><u> </u><u>and </u><u>+</u><u>3</u><u>3</u><u> </u><u>are </u><u>units</u><u> of</u><u> zero</u><u>.</u>

Hope it helps you...

( Answered by Benjemin)

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Andre and Priya are tracking the number of steps they walk. Andre records that he can walk 6000 steps in 50 minutes. Priya write
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Andre walks more steps than Priya.

To find out who many steps each one of them walks in a week, we have to carry out different calculations starting with Andre.

                 Calculation for number of steps taken by Andre

Andre takes 6000 steps in 50 minutes. We can use this information to scale up his number of steps over a period of 5 hours(300 minutes.). The quickest way to do this calculation, is to notice that there are 6 different 50 minute segments in 300 minutes. This means that the number of steps taken in 5 hours is 6\times 6000=36000 steps.

Another way to do this calculations is to use proportions

6000=50\\x=300\\=>50x=300\times6000=1800000\\=>x=36000.

Andre takes 36000 steps that week.

                 Calculation for number of steps taken by Priya

The number of steps taken by Priya is given by the is given by the function y=118x where x is the time in minutes. Priya walks for a total of 5 hours or 300 minutes. We calculate the number of steps she takes as shown below,

y=118x\\y=118\times 300\\y=35400.

Priya takes a total of 35400 steps.

Since  36000 steps is greater than 35400 steps, we conclude that Andre walks more steps than Priya.

3 0
3 years ago
When records were first kept (t=0), the population of a rural town was 260 people. During the following years, the population gr
Firdavs [7]

Answer:

(a) The population after 15 years is 2678.

(b)Therefore the population P(t) at any time t>0 is

P(t)= 45t+30 {t^{\frac32}}+260

Step-by-step explanation:

Given that,

The population grew at a rate of

P'(t)=45(1+\sqrt t)

Integrating both sides

\int P'(t) dt=\int 45(1+\sqrt t)dt

\Rightarrow \int P'(t) dt=\int (45+45\sqrt t)dt

\Rightarrow \int P'(t) dt=\int 45\ dt+\int 45\sqrt t\ dt

\Rightarrow P(t)= 45t+45\  \frac{t^{\frac12+1}}{\frac12+1}+c              [ c is integration constant]

\Rightarrow P(t)= 45t+45\  \frac{t^{\frac32}}{\frac32}+c

\Rightarrow P(t)= 45t+45\times\frac 23 \times {t^{\frac32}}+c

\Rightarrow P(t)= 45t+30 {t^{\frac32}}+c

When t=0 , P(0)= 260

\therefore 260= 45\times0+30\times {0^{\frac32}}+c

\Rightarrow c=260

\therefore P(t)= 45t+30 {t^{\frac32}}+260

Therefore the population P(t) at any time t>0 is

P(t)= 45t+30 {t^{\frac32}}+260

To find the population after 15 years, we need to plug t=15 in the above expression.

P(15)=( 45\times 15)+30( {15^{\frac32}})+260

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The population after 15 years is 2678.

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