Answer:
the GCF of 64 and 48 is 16
Step-by-step explanation:
Factors of 64: 1, 2, 4, 8, 16, 32 and 64.
Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48.
Common factors of 48 and 64: 1,2,4,8,16
solution:-We know that for any two finite sets A and B, n(A∪B)=n(A)+n(B)−n(A∩B).
Here, it is given that n(A)=20,n(B)=30 and n(A∪B)=40, therefore,
n(A∪B)=n(A)+n(B)−n(A∩B)
⇒40=20+30−n(A∩B)
⇒40=50−n(A∩B)
⇒n(A∩B)=50−40
⇒n(A∩B)=10
Hence, n(A∩B)=10
hope it helps you friend ☺️
Answer: the answer is A. point
