Answer:
180 i think if you are not sure with my ans then just don't use it k bey
Step-by-step explanation:
Answer:
27 ft
the maximum height of the arrow is 27 ft
Step-by-step explanation:
Given;
The height of the arrow is given by the function;
h(t) = -16t^2 + 32t + 11
Maximum height is at point when dh(t)/dt = 0.
Differentiating h(t), we have;
dh/dt = -32t + 32 = 0
Solving for t;
-32t = -32
t = -32/-32 = 1
t = 1 (time at maximum height is t = 1)
Substituting t=1 into h(t), to determine the value of maximum height;
h(max)= -16(1^2) + 32(1) + 11
h(max) = 27 ft
the maximum height of the arrow is 27 ft.
<span>We have the sequence that follows the pattern: a n = - 4 n + 13. If we want to calcelate the 14th term in this sequence ( or a 14 ), we have to substitute in this formula: n = 14. Then we will get: a 14 = - 4 * 14 + 13 a 14 = - 56 + 13, and finally: a 14 = - 43. Answer: The 14th term in the sequence is - 43.</span>
