Answer:
P(X= k) = (1-p)^k-1.p
Step-by-step explanation:
Given that the number of trials is
N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.
Given p = success,
1 - p = failure
Hence the distribution is described as: Pr ( FFFF.....FS)
Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p
Pr((X=k) = (1 - p)^ (k-1) .p
Since N<=k
Pr (X =k) = p(1-p)^k-1, k= 1,2,...k
0, elsewhere
If the probability is defined for Y, the number of failure before a success
Pr (Y= k) = p(1-p)^y......k= 0,1,2,3
0, elsewhere.
Given p= 0.2, k= 3,
P(X= 3) =( 0.2) × (1 - 0.2)²
P(X=3) = 0.128
Answer:
x^2+6x-4=0 x^2+6x=4 x^2+6x+9=13 (x+3)(x+3)=13 x+3=+or-(13^1/2) x=-3+or-13^1/2
Step-by-step explanation:
sry if im wrong :< if im right, can i have brainliest? have a wonderful day/night :D
The city is expotentially increasing in regards to population because Candice inhabits the area.
5.21 would just be 5 or 5.2 depending on what place you need to round.
Its1. every number/variable that has a power to the zero, its goin to turn out to be just one
