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kkurt [141]
3 years ago
10

Solve the equation. 3ln(2-x)=1 NEED ASAP thank you!

Mathematics
1 answer:
hjlf3 years ago
3 0

Answer:

0.6044 = x

Step-by-step explanation:

3ln(2-x)=1

In(2-x)= 1/3

2-x = e ^1/3

2-x = 1.3956

2-1.3956 = x

0.6044 = x

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Find the range and interquartile range for the data represented by the box plot.
Anarel [89]

<u>Given</u>:

Given that the data are represented by the box plot.

We need to determine the range and interquartile range.

<u>Range:</u>

The range of the data is the difference between the highest and the lowest value in the given set of data.

From the box plot, the highest value is 30 and the lowest value is 15.

Thus, the range of the data is given by

Range = Highest value - Lowest value

Range = 30 - 15 = 15

Thus, the range of the data is 15.

<u>Interquartile range:</u>

The interquartile range is the difference between the ends of the box in the box plot.

Thus, the interquartile range is given by

Interquartile range = 27 - 18 = 9

Thus, the interquartile range is 9.

3 0
3 years ago
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A rectangular box is 32 cm wide and 36 cm high. If the surface area of the box is 4344 square​ centimeters, find the length of t
AnnZ [28]

To find the surface area, multiply length x width x height.

let "length" = l

l x 32 x 36 = 4344

Simplify

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Isolate the length. Divide 1152 from both sides

(l x 1152)/1152 = (4344)/1152

l = 4344/1152

l = 3.77 (rounded)

3.77 cm is your length.

hope this helps

8 0
3 years ago
Someone please help me
amid [387]

Answer: that is equivalent to 447

Step-by-step explanation:

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Please help me quickly, timed test:(​
Dennis_Churaev [7]

Answer:

1 & 7

Step-by-step explanation:

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7 0
3 years ago
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NeX [460]

Answer:

Step-by-step explanation:

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So then you would take 1/2 of 17.

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3 years ago
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