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3 years ago

Solve the equation. 3ln(2-x)=1 NEED ASAP thank you!

Mathematics

1 answer:

hjlf3 years ago

3 0

Answer:

0.6044 = x

Step-by-step explanation:

3ln(2-x)=1

In(2-x)= 1/3

2-x = e ^1/3

2-x = 1.3956

2-1.3956 = x

0.6044 = x

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The drama club is selling T-shirts and caps to raise money for a spring trip. The caps sell for $5.00 each, and the T-shirts sel

Zinaida [17]

The required inequality is $5x+10y\geq 500$

<em><u>Solution:</u></em>

Given that,

Cost of 1 cap = $ 5

Cost of 1 t-shirt = $ 10

Let "x" be the number of caps sold

Let "y" be the number of t-shirts sold

The drama club needs to raise at least $500.00 for the trip

Based on this information, we can frame a inequality as:

number of caps sold x cost of 1 cap + number of shirts sold x cost of 1 shirt $\geq$ 500

Which means,

$x \times 5 + y \times 10\geq 500\\\\5x + 10y\geq 500$

Here we used "greater than or equal to" symbol , because club needs to raise at least $ 500

They can raise 500 or more than $ 500 also

Thus the required inequality is $5x+10y\geq 500$

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3 years ago

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Arisa [49]

Answer: y^2/x

Step-by-step explanation:

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2 years ago

Given the set of data: 24, 43, 65, 12, 31, 78, 43, 24, 25, 18, 29, 53, 18, 23, 20, 43, 53, 25 Determine the quartiles.

worty [1.4K]

Answer:

Lower quartile= 4.75

Middle quartile= 9.5

Upper quartile= 14.25

Step-by-step explanation:

The given date set is 24, 43, 65, 12, 31, 78, 43, 24, 25, 18, 29, 53, 18, 23, 20, 43, 53, 25

On counting them we notice that it's number of element is 18

So N = 18

Arranging them in ascending order gives

12,18,18,20,23,24,24,25,25,29,31,43,43,43,53,53,65,78

Lower quartile= (N+1)*1/4

Lower quartile= (18+1)/4

Lower quartile= 19/4

Lower quartile= 4.75

Middle quartile= (N+1)*2/4

Middle quartile= (18+1)*2/4

Middle quartile= (19)*2/4

Middle quartile= 9.5

Upper quartile= (N+1)*3/4

Upper quartile= (18+1)*3/4

Upper quartile= (19)*3/4

Upper quartile= 14.25

Inter quartile range = upper quartile- minutes lower quartile

= 14.25-4.75

= 9.5

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2 years ago

(4,7,12,19) How do you right this in recursive and explicit equations??????? pls help

Soloha48 [4]

You can see how the difference between two consecutive terms is constantly increasing:

$a_1 = 4$

$a_2 = 7 = 4+3$

$a_3 = 12 = 7+5$

$a_4 = 19 = 12+7$

So, for the next terms we'll have to add +9, +11, +13 and so on.

Also, note that $a_2$ is obtained by adding the 2nd odd number to $a_1$ , $a_3$ is obtained by adding the 3rd odd number to $a_2$ , and so on.

So, the recursive formula is

$a_n = a_{n-1}+(2n-1),\quad a_1=1$

For the explicit formula, recall that the sum of the first n odd numbers is n squared. Taking into account the fact that we're not starting from 1, we have

$a_n = n^2+3$

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3 years ago