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Phantasy [73]
3 years ago
13

Find a+b, 2a+3b,|a|, and |a-b|. a=3i-5j+3k, b=2j-k

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
3 0
A+b=(2i−4j+3k)+(2j− k)=2i−2j+2k 2a+3b =2(2i−4j+3k)+3(2j− k)
= 4 i−8 j + 6 k + 6 j − 3 k = 4 i − 2j + 3k
|a| = 22 +(−4)2 +32 = √29
|a−b| =|(2i−4j+3k)−(2j− k)|=|2i−6j+4k|
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Answer: P(256 ≤ x ≤ 433) = 0.951

Step-by-step explanation:

Since the weights of the fruit are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = weights of fruit.

µ = mean weight

σ = standard deviation

From the information given,

µ = 318 grams

σ = 37 grams

the probability that a fruit selected at random will weigh between 256 grams and 433 grams is expressed as

P(256 ≤ x ≤ 433)

For x = 256

z = (256 - 318)/37 = - 1.68

Looking at the normal distribution table, the probability corresponding to the z score is 0.048

For x = 433

z = (433 - 318)/37 = 3.1

Looking at the normal distribution table, the probability corresponding to the z score is 0.999

Therefore,

P(256 ≤ x ≤ 433) = 0.999 - 0.048 = 0.951

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3 years ago
A group of 8 friends go to the movies. A bag of popcorn costs $2.99. How much will it cost to get one bag of popcorn for each fr
Akimi4 [234]

Answer:

23.92

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
1
Hitman42 [59]

Answer:

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Answer:

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Step-by-step explanation:

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Firdavs [7]
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1 apple- 1.30 / 5
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