The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer:
sorry I can't help you. ...............
Step-by-step explanation:
A set of numbers is said to be Pythagorean triple if the sum of the squares of the lesser numbers equal the square of the remaining number,
A. 28² + 45² = 2809 ; 53² = 2809 ; EQUAL
B. 16² + 63² = 4225 ; 65²= 4225 ; EQUAL
C. 13² + 84² = 7225 ; 85² = 7225 ; EQUAL
D. 11² + 61² = 3842 ; 62² = 3844 ; NOT EQUAL
The answer is letter D.
Answer: The answer would be j=19
F(x) = 1 - x
f(-3) = 1 - (-3)
f(-3) = 4
