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2 years ago

(14v^7x^2-3v^7x^5)divided by (-2v^4x^3)

Mathematics

1 answer:

Dmitrij [34]2 years ago

5 0

.1 Simplify: 5n(2n3+n2+8)+n(4-n).

Solution:

5n(2n3+n2+8)+n(4-n).

= 5n × 2n3 + 5n × n2 + 5n × 8 + n × 4 - n × n.

= 10n4 + 5n3 + 40n + 4n – n2.

= 10n4 + 5n3 + 44n – n2.

= 10n4 + 5n3 – n2 + 44n.

Answer: 10n4 + 5n3 – n2 + 44n

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The answer is c. Because 8*8=64

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The amount of time a certain brand of light bulb lasts is normally distribued with a mean of 1800 hours and a standard deviation

DedPeter [7]

Answer: 68% of light bulbs last between 1765 hours and 1835 hours.

Step-by-step explanation:

The empirical rule states that for a normal distribution, nearly all of the data will fall within three standard deviations of the mean . The empirical rule is further illustrated below

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95% fall within two standard deviations.

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From the information given, the mean is 1800 hours and the standard deviation is 35 hours.

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3 years ago

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Tpy6a [65]

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Step-by-step explanation:

easy

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2 years ago

Two different suppliers, A and B, provide a manufacturer with the same part. All supplies of this part are kept in a large bin.

koban [17]

Answer:

The probability of selecting a non-defective part provided by supplier A is 0.807.

Step-by-step explanation:

Let A = a part is supplied by supplier A, B = a part is supplied by supplier B and D = a part is defective.

Given:

P (D|A) = 0.05, P(D|B) = 0.09

A supplies four times as many parts as B, i.e. n (A) = 4 and n (B) = 1.

Then the probability of event A and B is:

$P(A)=\frac{n(A)}{n(A)+N(B)}= \frac{4}{4+1}=0.80\\P(B)\frac{n(B)}{n(A)+N(B)}= \frac{1}{4+1}=0.20$

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$P(D)=P(D|A)P(A)+P(D|B)P(B)\\=(0.05\times0.80)+(0.09\times0.20)\\=0.058$

The probability of selecting a non-defective part provided by supplier A is:

$P(A|D')=\frac{P(D'|A)P(A)}{P(D')} = \frac{(1-P(D|A))P(A)}{1-P(D)}\\=\frac{(1-0.05)\times0.80}{(1-0.058)}\\ =0.80679\\\approx0.807$

Thus, the probability of selecting a non-defective part provided by supplier A is 0.807.

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3 years ago

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Strike441 [17]

Answer:

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Step-by-step explanation:

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2 years ago

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