Y+3=0 is vertical line -3 on the graph.
Hope this helps there was no choices.
1:40 because if we think of this just like a fraction

that simplifys down to

and because fraction simplifications are similar (related to each other) we can concur that these would be too.
Enjoy!=)
Answer:
the average rate of change is 4
Step-by-step explanation:
Using the binomial distribution, it is found that the mean and the standard deviation of variable x are given as follows:

<h3>What is the binomial probability distribution?</h3>
It is the probability of exactly <u>x successes on n repeated trials, with p probability</u> of a success on each trial.
The expected value of the binomial distribution is:
E(X) = np
The standard deviation of the binomial distribution is:

In this problem, we have that the parameters are given as follows:
n = 4, p = 0.75.
Hence the mean and the standard deviation are given as follows:
- E(X) = np = 4 x 0.75 = 3.
More can be learned about the binomial distribution at brainly.com/question/24863377
#SPJ1
The expression for the greatest common factor of 20 and 30 using the distributive property is 10(2 + 3)
Pounds of ice = 20
Number of cups = 30
The relation for the distributive property :
a × (b + c)
Expand ;
a × (b + c) = (a × b) + (a × c) = ab + ac
Finding the greatest common factor of 20 and 30 ;
(2 × 10) + (3 × 10)
According to the distributive property
(2 × 10) + (3 × 10) = 10(2 + 3)
Therefore, the expression for the greatest common factor is 10(2 + 3)
Learn more :brainly.com/question/15263211