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4 years ago

Help please I don’t know the answer

Mathematics

1 answer:

andrew-mc [135]4 years ago

8 0

Answer:

$16,534.95

Step-by-step explanation:

To compute interest on loans, we use the compounded interest equation. We use the equation $A=P(1+\frac{r}{n})^{nt}$ where

P is the principle or starting value

A is the total amount after interest and a period of time

r is the rate at which interest gathers as a decimal

t the time in years

n is the number of times compounded in a year.

For this problem, we know P=$8000, r=19%=0.19, t=4 years and n=2. We substitute into the formula and simplify to find the total amount A.

$A=P(1+\frac{r}{n})^{nt}\\A=8000(1+\frac{0.19}{2})^{2(4)}\\A=8000(1+0.095)^{8}\\A=16,534.95$

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4. h(x) = 2x^2 + 14x - 60

Step-by-step explanation:

Given that h(x) is a quadratic.

Also, h(3) = h(-10) = 0

(A) h(x) = x^2 - 13x - 30

=> h(3) = 3^2 - 13(3) - 30

=> h(3) = 9 - 39 - 30

=> h(3) = -30 - 30

=> h(3) = -60

=> h(3) ≠ 0

(B) h(x) = x^2 - 7x - 30

=> h(3) = 3^2 - 7(3) - 30

=> h(3) = 9 - 21 - 30

=> h(3) = -12 - 30

=> h(3) = -42

=> h(3) ≠ 0

=> h(3) = 2(3^2) + 26(3) - 60

=> h(3) = 2(9) + 78 - 60

=> h(3) = 18 + 78 - 60

=> h(3) = 96 - 60

=> h(3) = 36

=> h(3) ≠ 0

(D) h(x) = 2x^2 + 14x - 60

=> h(3) = 2(3^2) + 14(3) - 60

=> h(3) = 2(9) + 42 - 60

=> h(3) = 18 + 42 - 60

=> h(3) = 60 - 60

=> h(3) = 0

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=> h(-10) = 2(-10)^2 + 14(-10) - 60

=> h(-10) = 2(100) - 140 - 60

=> h(-10) = 200 - 200

=> h(-10) = 0

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=> h(3) = h(-10) = 0

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3 years ago

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2 years ago

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3 years ago

fire work a travels at the speed 300 ft/s firework b travels 240 ft/s. firework b is launched 0.25s before firework a. how many

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Both fireworks will explode after 1 seconds after firework b launches.

Step-by-step explanation:

Given:

Speed of fire work A= 300 ft/s

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How many seconds after firework b launches will both fireworks explode=?

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Let t be the time(seconds) after which both the fireworks explode.

By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation

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