Recall that
sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1
for all <em>θ</em>, and given that cos(<em>θ</em>) < 0, we find that
cos(<em>θ</em>) = -√(1 - sin²(<em>θ</em>)) = -√(1 - (2/5)²) = -√(21)/5
Now,
csc(<em>θ</em>) = 1/sin(<em>θ</em>) = 1/(2/5) = 5/2
and
cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>) = (-√(21)/5)/(2/5) = -√(21)/2
Answer:
The process is 'Squaring 1.4142135'
Step-by-step explanation:
We are given that,
1.4142135 is used repeatedly to approximate 2.
Now, we can see that ,
1.4142135 × 1.4142135 = 1.999999 ≅ 2
Thus, using the number 1.4142135 two times and taking their product approximates the number 2.
Hence, we used the process 'squaring the number 1.4142135' to obtain 2 approximately.