10.7 if I'm not mistaking
X-9 the answer is option a
Answer:
1) A
2) min; min; max; max
3) y = x² + 5x - 3
Step-by-step explanation:
f(x) = x² + 2(x)(5) + 5² - 5² + 24
f(x) = (x + 5)² - 25 + 24
f(x) = (x + 5)² - 1
In ax² + bx + c,
if a > 0, it's a min
if a < 0, it's a max
y = ax² + bx + c
Using (0,-3)
-3 = a(0)² + b(0) + c
c = -3
y = ax² + bx - 3
Using (1,3)
3 = a + b - 3
a + b = 6
Using (-1,-7)
-7 = a(-1)² + b(-1) - 3
-7 + 3 = a - b
a - b = -4
b = a + 4
a + (a + 4) = 6
2a = 2
a = 1
b = 5
y = x² + 5x - 3
Average rate=delta y/delta x...
c=(72-48-8+16)/(6-2)
c=32/4
c=8
Given:
Length of the cuboid tank = 4 m
Breadth = 2.5 m
Height = 2.4 m
One third of the tank is filled with water.
1 cubic meter = 1000 liters.
To find:
The quantity of the water in the tank.
Solution:
Volume of a cuboid is:

Where, l is length, b is breadth and h is the height.
The volume of the tank is :


Volume of tank is 24 cubic meter.
One third of the tank is filled with water. So, the volume of the water is

The volume of water is 8 cubic meters.
We have,
1 cubic meter = 1000 liters.
8 cubic meter = 8000 liters.
Therefore, the quantity of the water in the tank is 8000 liters.