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masya89 [10]
3 years ago
9

Find h. 10 in. h h = [?] in. 4 in.

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

h = sqrt(96)

Step-by-step explanation:

We can use the pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

2^2 + h^2 = 10^2

4 + h^2 = 100

h^2 = 100-4

h^2 = 96

Taking the square root of each side

h = sqrt(96)

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Find the perimeter of a 30°-60°-90° triangle with a hypotenuse of 18. a.P=27 +9/3^- c.p=24+6/3^- b.P= 27+9/6^- d. P=24+3/6^-
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note that for a 30°-60°-90° triangle , the sides are 1, √3, 2

If the hypotenuse (2) is equal to 18, find the other lengths

First, find side (1). Divide 18 by 2

18/2 = 9

Next, multiply 9 with √3

9(√3) = 9√3

Finally, find the perimeter. Add all sides:

P = 18 + 9 + 9√3

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8 0
3 years ago
A metallurgist has one alloy containing 30% copper and another containing 62% copper. How many pounds of each alloy must be used
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The metallurgist would need 46.875 lb of an alloy containing 30 % copper and 3.125 lb of an alloy containing 62 % copper to produce 50 lb of a third alloy.

<h3>How to estimate proportions of ingredients for an alloy by weighted averages</h3>

In this question we must prepare a <em>third</em> alloy by using correct quantity of two alloys with different <em>copper</em> concentrations. <em>Required</em> weights can be determined by applying concept of <em>weighted</em> average:

(32/100) · (50 lb) = (30/100) · x + (62/100) · (50 - x)

32 · 50 = 30 · x + 62 · (50 - x)

32 · 50 = 30 · x + 62 · 50 - 62 · x

32 · x = 30 · 50

x = 46.875

The metallurgist would need 46.875 lb of an alloy containing 30 % copper and 3.125 lb of an alloy containing 62 % copper to produce 50 lb of a third alloy.

To learn more on weighted averages: brainly.com/question/18554478

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2 years ago
Sonia read 2 pages of book per minute. If sonia read all the pages of the book at the same rate, which equation shows the tital
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