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aleksklad [387]

3 years ago

9

Which quadratic equation is equal to (x+2)^2+5(x+2)-6=0

2 answers:

ch4aika [34]3 years ago

7 0

Answer:

(x+2)^{2} +5(x+2)-6=0

Let

u=(x+2)

Substitute in the expression

(u)^{2} +5(u)-6=0

therefore

the answer is

(u)^{2} +5(u)-6=0 is equivalent to (x+2)^{2} +5(x+2)-6=0

brainly.com/question/6501456

lapo4ka [179]3 years ago

6 0

See attached for answer

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3√x -2/x^2<br><br>please show step by step of differentiation before combining the terms.

EastWind [94]

Answer:

Step-by-step explanation:

Before we differentiate, let us assign a variable to the function. Let y be equal to the function i.e let y = 3√x -2/x²

In differentiation if $y = ax^{n}$ , then $\frac{dy}{dx} = nax^{n-1}$ where n is a constant and dy/dx means we are differentiating the function y with respect to x.

Applying the formula o the question given;

$y= 3\sqrt{x} -2/x^2\\y = 3{x}^\frac{1}{2} - 2x^{-2} \\\\$

On differentiating the resulting function;

$\frac{dy}{dx} = \frac{1}{2}*3x^{\frac{1}{2}-1 } - (-2)x^{-2-1} \\\\\frac{dy}{dx} = \frac{1}{2}*3x^{-\frac{1}{2}} + 2x^{-3}\\ \\\frac{dy}{dx} = \frac{1}{2}*{\frac{3}{x^{\frac{1}{2} } }} + \frac{2}{x^{3} } \\\\\frac{dy}{dx} = {\frac{3}{2x^{\frac{1}{2} } }} + \frac{2}{x^{3} }\\\\\frac{dy}{dx} = {\frac{3}{2\sqrt{x} }} + \frac{2}{x^{3} }$

To combine the terms, we will add up by finding their LCM.

$\frac{dy}{dx} = {\frac{3}{2\sqrt{x} }} + \frac{2}{x^{3} }\\\frac{dy}{dx} = \frac{3x^3+4\sqrt{x} }{2x^{3} \sqrt{x}}$

3 0

4 years ago

Which correctly describes a cross section of the right rectangular prism if the base is a rectangle measuring 15 inches by 8 inc

lbvjy [14]

I'm pretty sure it's:

A right rectangular prism with length 15 inches, width of 8 inches, and height of 6 inches.

A cross section parallel to the base is a rectangle measuring 15 inches by 8 inches

A cross section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 6 inches by 15 inches

Just visualize the rectangle

8 0

3 years ago

Read 2 more answers

Plz help! ASAP! What is the expression shown below

astra-53 [7]

we are given

$\frac{1}{2} (\frac{3}{2} x+6x+1)-3x$

step-1: Simplify expression inside parenthesis

we will combine like terms

so, firstly we will take common denominator

$\frac{1}{2} (\frac{3}{2} x+\frac{2*6}{1*2}x+1)-3x$

$\frac{1}{2} (\frac{3x+12x}{2} +1)-3x$

$\frac{1}{2} (\frac{15x}{2} +1)-3x$

step-2: Distribute 1/2 inside

$=\frac{1}{2} *\frac{15x}{2} +1*\frac{1}{2}-3x$

$=\frac{15x}{4} +\frac{1}{2} -3x$

step-3: Combine like terms

$=\frac{15x}{4}+3x +\frac{1}{2}$

We can find common denominator

$=\frac{15x}{4}-\frac{4*3x}{4*1} +\frac{1}{2}$

$=\frac{15x}{4}-\frac{12x}{4} +\frac{1}{2}$

$=\frac{15x-12x}{4} +\frac{1}{2}$

$=\frac{3x}{4} +\frac{1}{2}$

we can also write it as in mixed form

$=\frac{3}{4}x +\frac{1}{2}$

so, we will get

$\frac{1}{2} (\frac{3}{2} x+6x+1)-3x=\frac{3}{4}x +\frac{1}{2}$

option-C.............Answer

5 0

4 years ago

Zoe invested $16,000 in an account paying an interest rate of 3.6% compounded

Diano4ka-milaya [45]

Answer:

Its 32800

Step-by-step explanation:

6 0

3 years ago

Which of the following are equal to the expression below? check all that apply

malfutka [58]

Are you serious?

The correct answers are B. , D. and E.

Good luck!!!!

3 0

3 years ago