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3 years ago

The probability of having a head in a single toss of a coin is?

Mathematics

2 answers:

Verizon [17]3 years ago

4 0

Answer:

50%

Step-by-step explanation:

you have ONLY two possibility's which means the probablility of your coin landing a heads in 1/2 of 100% (the total probability),...

Happy flipping,...with the coins,... and BEST of luck flipping a washington (that is if you are using a quarter,...)

Chow,...!

olga nikolaevna [1]3 years ago

3 0

Answer:

probability will be 1/2 because when you toss a single coin then there will be 2 outcomes: a head and a tail that is 2 possible outcomes so, the probability of getting a hard in a single toss of coin will be 1/2

explanation:

hope it helps

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Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx....%7D%20%7D%20%7D%20%7D%20%20%3D%20%

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First observe that if $a+b>0$ ,

$(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}$