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3 years ago

What percent of 200 is 40?a. 200%b. 20%c. 2%

Mathematics

2 answers:

OleMash [197]3 years ago

7 0

Answer:

20%

Step-by-step explanation:

if you take 40/ 200 = 20

just olya [345]3 years ago

5 0

Answer:

20%

Step-by-step explanation:

convert the fraction to 40/200

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-0.113 blank =0.452x + 0.452

nataly862011 [7]

Answer:

a=-4

b=-4

Step-by-step explanation:

-0.113 blank =0.452x + 0.452

-0.113(a+bx) =0.452x + 0.452

-0.113a-0.113bx =0.452x + 0.452

so we have

-0.113a=0.452

a=-0.4520/0.113= -4

-0.113bx =0.452x

b=-0.452/0.113= -4

8 0

3 years ago

A recipe uses 8 3/4 cups of milk for every 3 1/2 cups of oatmeal.

Dennis_Churaev [7]

1 1/2 cups of milk for every cup of oatmeal.

8 3/4=8.75 3 1/2=3.50 8.75÷3.50→875÷350=2 175/350

175=1/2 of 350

4 0

3 years ago

Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

3 years ago

A patio uses 42 square meters of tile to cover the floor. The width of the patio is 6 meters. What is the length of the patio

MrMuchimi

Answer:

Step-by-step explanation:

42 meters divided by 6 meters = 7 meters

4 0

3 years ago

Which statement is true?

Veronika [31]

Answer:

B. Only 140 is an outlier

Step-by-step explanation:

To properly identify an outlier, you must first know what it is. An outlier is a number that is either a lot higher or a lot lower than the average in a set of numbers. For example, if you had a number set of 1, 3, 4, 6, and 72, you can deduce that 72 is the outlier because it's very far away compared to the other numbers in the set.

In the set that's provided, the numbers tend to range in the double digits, going up in small increments from 15 to 89. However, we can see that 140 is a lot higher than the rest of the numbers in the set, so we can assume that 140 is an outlier.

7 0

3 years ago

Read 2 more answers

What percent of 200 is 40?a. 200%b. 20%c. 2%​

What percent of 200 is 40?a. 200%b. 20%c. 2%