In the u.s.all financial institutions are required to conduct business at a physical location only

4.15 LAB: Mad Lib - loops Mad Libs are activities that have a person provide various words, which are then used to complete a sh

Sergio039 [100]

Answer:

Following are the program in the Python Programming Language.

#set the infinite while loop

while(True):

#get string input from the user

name=input()

#get integer input from the user

num=int(input())

#set the if statement to break the loop

if(num==0):

break

#otherwise, print the following output

else:

print("Eating {} {} a day keeps the doctor away.".format(num, name))

<u>Output</u>:

oranges

5

Eating 5 oranges a day keeps the doctor away.

apple

0

Explanation:

<u>Following are the description of the program</u>:

Set the loop that iterates at infinite times and inside the loop.
Declare two variables which are 'name' that get string type input from the user and 'num' that get integer type input from the user.
Set the if conditional statement for break the infinite while loop.
Otherwise, it prints the following output.

7 0

3 years ago

Allison is preparing to modify a network access control list and add three firewall rules to her private cloud HR systems. She i

Yakvenalex [24]

C. Change management

Allison is preparing to modify a network access control list and add three firewall rules to her private cloud HR systems by following the Change management process.

What exactly is change management?

Change management is the process of developing and implementing effective change strategies in businesses and organizations.

Examining the reasons for change, implementing changes, and assisting people in adapting to these changes are all part of it. This could include reorganizing the workforce, implementing new technology, lowering costs, increasing profits, or a combination of these to achieve a specific goal.

To know more about Change management, visit: brainly.com/question/28096717

#SPJ4

4 0

1 year ago

Consider the following class declaration: public class Square { private double sideLength; public double getArea() { return side

kipiarov [429]

Answer:

Here is the constructor:

public Square(double s) { //constructor name is same as class name

sideLength = s; } //s copied into sideLength field

Explanation:

The above constructor is a parameterized constructor which takes a double type variable s as argument. The name of constructor is same as the name of class.This constructor requires one parameters. This means that all declarations of Square objects must pass one argument to the Square() constructor as constructor Square() is called based on the number and types of the arguments passed and the argument passed should be one and of type double.

Here is where the constructor fits:

public class Square {

private double sideLength;

public Square(double s) {

sideLength = s; }

public double getArea() {

return sideLength * sideLength;}

public double getSideLength() {

return sideLength; } }

4 0

3 years ago

Write a function with two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The func

Allisa [31]

Answer:

Here is the program:

#include <iostream> //to use input output functions

#include <string> // to use functions to manipulate strings

using namespace std; //to identify objects cin cout

void function(string prefix, unsigned int levels){ // function that takes two parameters, a string, using the string class and levels an unsigned integer

if (levels == 0) { //if number of levels is equal to 0

cout << prefix << endl; //displays the value of prefix

return; }

for (int i = 1; i <=9 ; i++){ //iterates 1 through 9 times

string sections = (levels == 1 ? "" : "."); //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

string output = prefix + std::to_string(i) + sections; // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

function(output, levels - 1); } } //calls function by passing the resultant string and levels-1 recursively to print the string prefix followed by section numbers

int main() { // start of main function

int level = 2; //determines the number of levels

function("BOX", level); } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix + std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix + std::to_string(i) + sections; statement becomes

string output = BOX + 2

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix + std::to_string(i) + sections; statement becomes

string output = BOX + 3

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix + std::to_string(i) + sections; statement becomes

string output = BOX + 9

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1 BOX2 BOX3 BOX4 BOX5 BOX6 BOX7 BOX8 BOX9

The program along with the output is attached.

4 0

3 years ago

How do you feel about the Furry Fandom?

gtnhenbr [62]

When you don’t know who or what that is, and I pop- lol I need a life

8 0

3 years ago